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Feliz [49]
4 years ago
6

mes {4x}y^4{?} " alt=" {4x}^2 \times {4x}y^4{?} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
timurjin [86]4 years ago
4 0
The first step for solving this expression is to multiply 4 by 4.
16x² × xy^{4}
Remember that if a term doesn't have an exponent,, it is considered that the exponent is actually 1. This changes the expression to the following:
16x² × x^{1}y^{4}
Now multiply the terms with the same base by adding their exponents.
16x^{2+1}y^{4}
Lastly,, add the exponents together to get your final answer.
16x³y^{4}
Let me know if you have any further questions.
:)
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myrzilka [38]
I think it’s 7? Maybe because of the division
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What is the area of the composite shape below?​
Hatshy [7]
5*2=10
10+12*4.5=64cm^2

Hope it helps
5 0
3 years ago
WILL MARK BRAINLIEST Using the function
Blizzard [7]

Answer:

B

Step-by-step explanation:

B. The independent variable is d.

7 0
3 years ago
Read 2 more answers
A model rocket is launched with an initial upward velocity of 30 m/s. The rockets height (in meters) after t seconds is given by
daser333 [38]

9514 1404 393

Answer:

  t = 3-√7 and 3+√7 seconds after launch

Step-by-step explanation:

You want to find the values of t that make h=10.

  10 = 30t -5t^2

  t^2 -6t = -2 . . . . . divide by -5

  t^2 -6t +9 = 7 . . . add 9 to complete the square

  (t -3)^2 = 7 . . . . . write as a square

  t -3 = ±√7 . . . . . . take the square root

  t = 3 ±√7 . . . . . . values of t for which height is 10 meters

__

These values are about 0.354 seconds, and 5.646 seconds.

5 0
3 years ago
I need help!! please, you don’t even have to do it all just explain to me how to do the first one I’ll catch on
lisov135 [29]

Hi there!

<u>What we need to know:</u>

The three main trigonometric ratios are sine, cosine and tangent:

\displaystyle sin\theta=\frac{opposite}{hypotenuse}     \displaystyle cos\theta=\frac{adjacent}{hypotenuse}    \displaystyle tan\theta=\frac{opposite}{adjacent}

"Opposite" refers to the side opposite the angle that is not the hypotenuse.

"Hypotenuse" refers to the side opposite the right angle of a right triangle.

"Adjacent" refers to the side next to the angle that is not the hypotenuse.

"θ" is read as "theta". It just represents the angle.

Keep in mind that these three ratios only apply to right triangles.

You can use the mnemonic "soh-cah-toa" to help you remember these ratios.

<u>First question</u>

For the first question, we're given the angle with a measure of 56 degrees and the length of the <em>hypotenuse</em>. We must calculate <em>a</em>, which represents the side <em>adjacent </em>to the given angle.

Given the hypotenuse and the adjacent side, we know that we must use the cosine ratio:

\displaystyle cos\theta=\frac{adjacent}{hypotenuse}

Plug in the given information:

\displaystyle cos56=\frac{a}{13}

Isolate <em>a</em> by multiplying both sides by 13:

13\displaystyle cos56=a

Solve using a calculator:

a=7.3

Therefore, <em>a</em> is equal to 7.3 when rounded to 1 decimal place.

<u>Other information you will need to know:</u>

In the above question, we needed to solve for a side. But what if we were given two sides and we needed to solve for an angle? For example:

\displaystyle sin\theta=\frac{5}{8}

In this case, we will use the inverse sine ratio:

\displaystyle \theta=sin^-^1(\frac{5}{8})

Solve using a calculator:

\displaystyle \theta=39

Therefore, the angle would equal approximately 39 degrees.

I hope this helps!

3 0
3 years ago
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