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3 years ago

What form of communication are they using

Computers and Technology

1 answer:

Troyanec [42]3 years ago

7 0

Answer:

They are using a writing form of communication.

Explanation:

Letters can be used to communicate between two or more people.It is a very easy mean of communicating.

Hope this helps

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3. Why did Steve Jobs and Steve Wozniak start working on developing computers?

LenaWriter [7]

Jobs was less hands-on when it came to developing computer software, and instead focused on design, advertising and talking to press, Wozniak said. “One thing he wanted was to somehow be important in the world, though he didn't have the academic or business, background, he had me,” he said.

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4 years ago

The following is a function:

Lunna [17]

Answer:

Explanation:

i took test

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2 years ago

The network services and facilities that users interact with are provided by

docker41 [41]

<span>The network services and facilities that users interact with are provided by authentication.</span>

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3 years ago

Questions: 1) Run the C program, attach a screenshot of the output in the answer sheet. 2) Check the address of the array and th

KiRa [710]

Answer:

Output

mumners = 0x7ffc4d2767d0

Method1: Address of array Elements

numbers[0] = 0x7ffc4d2767d0

numbers[1] = 0x7ffc4d2767d4

numbers[2] = 0x7ffc4d2767d8

numbers[3] = 0x7ffc4d2767dc

numbers[4] = 0x7ffc4d2767e0

Method2: Address of array Elements

numbers[0] = 0x7ffc4d2767d0

numbers[1] = 0x7ffc4d2767e4

numbers[2] = 0x7ffc4d2767f8

numbers[3] = 0x7ffc4d27680c

numbers[4] = 0x7ffc4d276820

sizeof(numbers) = 20

mumners = 0x7ffc4d2767d0

Method1: Address of array Elements

numbers[0] = 0x7ffc4d2767d0

Yes both are same since address of the array is the address of its first element

Method1: Address of array Elements

numbers[0] = 0x7ffc4d2767d0

numbers[1] = 0x7ffc4d2767d4

numbers[2] = 0x7ffc4d2767d8

numbers[3] = 0x7ffc4d2767dc

numbers[4] = 0x7ffc4d2767e0

Method2: Address of array Elements

numbers[0] = 0x7ffc4d2767d0

numbers[1] = 0x7ffc4d2767e4

numbers[2] = 0x7ffc4d2767f8

numbers[3] = 0x7ffc4d27680c

numbers[4] = 0x7ffc4d276820

Address printed using Method1 and Method2 are same since name of the array itself a pointer and adding 1 to it gives second element address and 2 to it gives third element and so on similarly applying address operator over the array elements provides the direct address of the element.

printf("Length(numbers) = %lu\n",sizeof(numbers)/sizeof(numbers[0]));

Dividing an size of array by size of individual array elements gives length of an array

Length(numbers) = 5

Yes even if numbers are passed to a function sizeof can be applied since numbers is starting address of an array and to pass an array as argument its address passed.

5 0

3 years ago

Write the definition of a function named quadratic that receives three double parameters a, b, c. If the value of a is 0 then th

VMariaS [17]

Answer:

#include <iostream>

#include <cmath>

using namespace std;

//initialize function quadratic

void quadratic(double, double, double);

int main() {

//declare double variables a, b and c

double a,b,c;

//take input from user

cin>>a>>b>>c;

//call function quadratic

quadratic(a,b,c);

return 0;

}

void quadratic(double a, double b, double c){

double root,n;

//check if variable a is equal to zero

if(a==0){

cout<<"no solution for a=0"<<endl;

return;

}

//check if b squared - 4ac is less than zero

else

if(((b*b)-(4*a*c))<0){

cout<<"no real solutions"<<endl;

return;

}

//print the largest root if the above conditions are not satisfied

else{

n=((b*b)-(4*a*c));

root=(-b + sqrt(n)) / (2*a);

cout<<"Largest root is:"<<root<<endl;

}

return ;

}

Explanation:

Read three double variables a, b and c from the user and pass it to the function quadratic. Check if the value of variable a is equal to zero. If true, print "no solution for a=0". If this condition is false, check if b squared - 4ac is less than zero. If true, print "no real solutions". If this condition is also false, calculate the largest solution using the following formula:

largest root = (-b + square root of (b squared - 4ac)) / (2*a)

Input 1:

2 5 3

Output 2:

Largest root is:-1

Input 2:

5 6 1

Output 2:

Largest root is:-0.2

5 0

4 years ago

What form of communication are they using​

What form of communication are they using