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zaharov [31]
3 years ago
11

What percent of 300 is .06

Mathematics
2 answers:
cestrela7 [59]3 years ago
8 0
0.02% of 300 is .06

Change 0.06 and 300 and change into fraction: 0.06/300
Convert 0.06/300 into decimal: 0.0002
Multiply decimal by 100: 0.0002 × 100 = 0.02% <-- our answer
zubka84 [21]3 years ago
8 0
'of' in mathematics means multiplication
'is' in mathematics means equal 

We are solving for x.

x% can also be written as x/100

\frac{x}{100} \times 300 = 0.06\\\\3x = 0.06\\\\\boxed{\bf{x = 0.02}}

0.02% of 300 is 0.06
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4 years ago
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Write Y=x^2+18x+90 In vertex form
Elena-2011 [213]

Answer:

y = (x + 9)² + 9

Step-by-step explanation:

the equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

given a parabola in standard form : ax² + bx + c : a ≠ 0

the the x-coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

y = x² + 18x + 90 is in standard form

with a = 1, b= 18 and c = 90

x_{vertex} = - \frac{18}{2} = - 9

to find the corresponding y-coordinate substitute x = - 9 into the equation

y = (- 9)² + 18(- 9) + 90 = 81 - 162 + 90 = 9

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6 0
3 years ago
Someone please help!!
Wittaler [7]
A. (X+7)^2
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3 0
3 years ago
Sinx =căn 2/3<br> sinx=5/4<br> sinx =1<br> sin3x=can3/2<br> sin(x-60)=-1/2<br> sin3x=1/2
mel-nik [20]

Answer:

Correct option is

B

0

D

−1

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=sin(2x−x)+sin2x+sin(2x+x)

=2sin2xcosx+sin2x [ by using sin(A+B)=sinAcosB+sinBcosA and sin(A−B)=sinAcosB−sinBcosA ]

=sin2x(2cosx+1)........(i)

cosx+cos2x+cos3x

=cos(2x−x)+cos2x+cos(2x+x)

=2cos2xcosx+cos2x [By using cos(a−b)=cosa⋅cosb+sina⋅sinb and cos(a+b)=cosa⋅cosb−sina⋅sinb]

=cos2x(2cosx+1).....(ii)

∴(sinx+sin2x+sin3x)

2

+(cosx+cos2x+cos3x)

2

=1

sin

2

2x(2cosx+1)

2

+cos

2

2x(2cosx+1)

2

=1.......[From(i)(ii)]

⇒(2cosx+1)

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⇒2cosx+1=±1

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6 0
3 years ago
a man has been driving a second hand car for the past four years. over these four years he managed to save 16% as a deposit of t
Ksenya-84 [330]

Answer:

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Step-by-step explanation:

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7 0
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