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aleksklad [387]
3 years ago
14

Can someone help me on number 16 !!!!!

Mathematics
1 answer:
kap26 [50]3 years ago
5 0

Answer:

number 16 there i spelled it.

Step-by-step explanation:

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In parallelogram ABCDABCD, ∠A∠A and ∠B∠B are adjacent. The measure of ∠B∠B is two times the measure of ∠A∠A. Which equation give
77julia77 [94]
Since adjacent angles in a parallelogram are supplementary (they add up to 180°), and ∠B is double as ∠A, you have this equation:

∠A + 2·∠A = 180°

From that you can find: 3·∠A = 180° ⇒ ∠A = 60°.
3 0
3 years ago
A silk ribbon costs $5.60 for 0.8m. Find the constant of variation.
Minchanka [31]

Answer: The constant of variation value of 7.


Step-by-step explanation: We are given cost of 0.8 meter of a silk ribbon = $5.60.

Let us assume y be the total cost for x meter of a silk ribbon and k is the  constant of variation.

So, we can set up an equation for proportion relationship:

y = k x.

<em>Let us plug x=0.8 and y= 5.60,</em> in above proportion relationship equation, we get

5.60 = k (0.8).

Dividing both sides by 0.8, we get

5.60/0.8 = k(0.8)/0.8

k =7.

Therefore, the constant of variation value of 7.



6 0
3 years ago
This ones a tuff one (algebra)
babymother [125]

13x^2 + 2.8x

Step-by-step explanation:

you combine light terms

5 0
3 years ago
When a number is a multiple of another, the GCF of the numbers is the greater of the numbers. Is this always, sometimes, or neve
Mice21 [21]
It depend actually on the number u r given
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3 0
3 years ago
Calculate the density of benzene if 0.10L has a mass of 36.4g.
adelina 88 [10]

Answer:

d=0.364\ g/cm^3

Step-by-step explanation:

It is given that,

Mass of benzene, m = 0.1 L

Mass, m = 36.4 g

We know that, 1 L = 1000 cm³

0.1 L = 100 cm³

The density of an object is equal to its mass divided by its volume. So,

\rho=\dfrac{m}{V}\\\\=\dfrac{36.4\ g}{100\ cm^3}\\\\=0.364\ g/cm^3

So, the density of benzene is 0.364\ g/cm^3.

8 0
3 years ago
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