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Lena [83]
3 years ago
8

Find the value of each variable.

Mathematics
2 answers:
otez555 [7]3 years ago
7 0

Answer:

(A)

Step-by-step explanation:

From the figure, since RT is parallel to QU, therefore ΔSQU is similar to ΔSRT, thus using the basic proportionality theorem, we get

\frac{SR}{SQ}=\frac{ST}{SU}

\frac{c}{12+c}=\frac{10}{25}

25c=120+10c

15c=120

c=8

Also, QU is parallel to PV, therefore from ΔPVS and ΔSRT, we have

\frac{SR}{SP}=\frac{ST}{SV}

\frac{c}{c+12+d}=\frac{10}{30}

\frac{8}{20+d}=\frac{1}{3}

24=20+d

d=4

Now, from ΔSRT and SQU, we have

\frac{RT}{QU}=\frac{ST}{SU}

b=\frac{10{\times}12.5}{25}

b=5

Also, from ΔSQU and SPV,

\frac{12.5}{a}=\frac{25}{30}

a=15

Thus, value of a,b,c and d are 15,5,8 and 4 respectively.

sergejj [24]3 years ago
6 0
I'm pretty sure its A
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Find the max/min value of f(x) = 2x2 + 3x - 5
Lelechka [254]

Answer:

The minimum value is (-\frac{3}{4},-\frac{49}{8}) or  (-0.75,-6.125)

Step-by-step explanation:

we have

f(x)=2x^{2}+3x-5

This is the equation a vertical parabola open upward

The vertex represent a minimum

The general equation in vertex form is

f(x)=a(x-h)^2+k

where

(h,k) is the vertex

Convert the given function in vertex form

f(x)=2x^{2}+3x-5

Factor 2

f(x)=2(x^{2}+\frac{3}{2}x)-5

Complete the square

f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-5-\frac{9}{8}

f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-\frac{49}{8}

Rewrite as perfect squares

f(x)=2(x+\frac{3}{4})^{2}-\frac{49}{8}

The vertex is the point (-\frac{3}{4},-\frac{49}{8})

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Step-by-step explanation:

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8 0
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