Hope this helps. Domain and range are the same for this question.
Answer:
100/9
Step-by-step explanation:
(7*5*2/7*3)² * (5^0/2^-3)³ * 2^-9
Solution:
We know that any number with power 0 = 1
(7*5*2/7*3)² * (1/2^-3)³ * 2^-9
Now cancel out 2 by 2
= (7*5*2/7*3)² * (1/1^-3)³ * 1^-9
=(70/21)² * (1)³/(1^-3)³ * 1^-9
=(10/3)^2 * 1/1^-1 * 1/1^9
=100/9 *1 *1
=100/9....
Answer:
13
Step-by-step explanation:
it is very easy
19-6=-11
it is false
now the true equation is
19-6= 13
Answer:
मअजदलविििृससफफददअअअअखल ,र।।
<span>Data:
infinite geometric series
A1
= 880
r = 1 / 4
The sum of a geometric series in sigma
notation is:
n 1 - r^n
∑ Ai = A ----------- ; where A = A1
i = 1 1-r
When | r | < 1 the infinite sum exists and is equal to</span><span><span>:
∞ A
∑ Ai = ---------- ; where A = A1
i = 1 1 - r</span>
So, in this case</span><span><span>:
∞ 880
∑ Ai = -------------- = 4 * 880 / 3 = 3520 /3 = 1173 + 1/3
i = 1 1 - (1/4)</span> </span>
Answer: 1173 and 1/3
