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4 years ago

I. A biologist walks along a beach and notices that 60% of observed ghost crabs have one claw that is larger than the other.

Mathematics

1 answer:

OLga [1]4 years ago

5 0

Answer:

C i-statistic,ii) statistics III) statistics iv) statistics v) statistics

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Lilla read 1/5 of her book last week. This week she read 3 times as much as she read last week. Write an expression to show how

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The solution is in the attachment

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3 years ago

The time t it takes Sam to drive to his grandmothers jouse

8_murik_8 [283]

What is the rest of the question?

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4 years ago

Find the value of x. Round your answer to the nearest tenth.

natka813 [3]

That's a question about the Pythagorean Theorem.

We use the Pythagorean Theorem to find the value of one side in a right triangle.

This theorem says that:

$\boxed{a^2 = b^2 + c^2}$

a is the hypotenuse (It's the opposite side the right angle).
b and c are cathetus (They're the adjacent sides the right angle).

Okay, now, let's go to solve this problem! In our figure, we have two cathetus. Their values are 10 and 7 and we have to find the value of x (the hypotenuse). Let's change this information in that formula.

$a^2 = b^2 + c^2\\x^2 = 10^2 + 7^2\\x^2 = 100 + 49\\x^2 = 149\\x = \sqrt{149}$

Therefore, the value of x is $\sqrt{149}$ .

I hope I've helped. :D

Enjoy your studies! \o/

5 0

3 years ago

Find the center and the radius of this equation by completing the

Colt1911 [192]

Answer:

$x^2 +4x +(4/2)^2 +y^2 -20 y +(20/2)^2 +100 = (4/2)^2 +(20/2)^2$

And solving we got:

$x^2 +4x+ 4 +y^2 +20y +100 +100 = 4 +100$

If we subtract 100 from both sides we got:

$(x+2)^2 +(y+10)^2 = 4$

$C= (-2,-10)$

$r = \sqrt{4}=2$

Step-by-step explanation:

For this case we have the following equation given:

$x^2 +4x +y^2 -20 y +100=0$

We want to find a general expression given by:

$(x-h)^2 +(y-k)^2 = r^2$

Where the center is (h.k) and the radius is r.

We can begin completing the squares of the equation given and we got:

$x^2 +4x +(4/2)^2 +y^2 -20 y +(20/2)^2 +100 = (4/2)^2 +(20/2)^2$

And solving we got:

$x^2 +4x+ 4 +y^2 +20y +100 +100 = 4 +100$

If we subtract 100 from both sides we got:

$(x+2)^2 +(y+10)^2 = 4$

Then we can conclude that the center is:

$C= (-2,-10)$

And the radius would be:

$r = \sqrt{4}=2$

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3 years ago

Which equation is NOT true when k = -18?

a_sh-v [17]

Answer:

a. po yung answer

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3 years ago

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