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3 years ago

Write the phrase for the following expression: 378 x (56-34

Mathematics

1 answer:

Nonamiya [84]3 years ago

5 0

378 X 56 - 34 =21,134

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The answer is 8a^3-27b^3

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3 years ago

Hi, can someone help me on these 2 as quick as possible please, ty!!

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4 years ago

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A 4 pound roast must be cooked for 30 minutes per pound and must rest for 15 minutes when must it be put into the oven in order

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3 years ago

A random sample of 401 student were recent survey regarding their class standing freshmen software junior senior and their major

SOVA2 [1]

the Solution

$Pr(\text{STEM)}=\frac{158}{401}=0.394$ $Pr(\text{Sophomore)}=\frac{87}{401}=0.217$ $Pr(sophomore|Non-stem)=\frac{68}{401}=0.170$ $Pr(\text{sophomore and Non-stem)=}\frac{87}{401}\times\frac{243}{401}=\frac{21141}{160801}=0.1315$

To ascertain whether Sophomore and Non-stem are dependent, we have to test the following:

$\begin{gathered} If\text{ Pr(sophomore or Non-stem) = Pr(sophomore and Non-stem),} \\ \text{then we conclude that both events are Independent,} \\ \text{otherwise, they are dependent.} \end{gathered}$ $\begin{gathered} Pr(\text{sophomore or Non-stem)=Pr(sophomore)+Pr(Non-stem)} \\ -Pr(\text{sophomore and Non-stem)} \end{gathered}$ $Pr(\text{Sophomore or Non-stem)=}\frac{87}{401}+\frac{243}{401}-(\frac{87}{401}\times\frac{234}{401})$ $=\frac{330}{401}-\frac{21141}{160801}=0.82294-0.13147=0.69147$

Cleary, we have that sophomore and non-stem events are dependent events since 0.69147 is not the same as 0.13147.

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1 year ago

Factor the expression.<br> x^3+8

Aneli [31]

X^3+8
= x^3+2^3

<span>a^3 + b^3 = (a + b)(a^2 – ab + b^2)</span>

so

x^3+8
= x^3+2^3
= (x+2)(x^2-2x+2^2)
= (x+2)(x^2-2x+4)

3 0

3 years ago