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2 years ago

One way in which the motives for the Arab Spring and for the French Revolution are similar is that people wanted to

1 answer:

4 0

The answer is 2. <span>Alter the government to bring about reform
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The Arab Spring and the French Revolution were both reactions to a system seen as unjust to the ordinary people of the country.

The citizens of the nations stood together against a dictator, tyrant and an absolute King who did not like to share power and did not believe in the will of the people.

For common people during the French revolution and the Arab Spring, there were few economic opportunities. Freedom of Speech were strictly curtailed and minorities were oppressed.

Both movements also led to several clashes between government forces and rebels causing hundreds of deaths and thousands of injuries.

Till date, the success of both the French Revolution and the Arab Spring highly debated among academics.
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3 years ago

. If the fastest passenger aircraft can fly 0.45 km/s (1000 mph), how long would it take to reach the sun? The galactic center?

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Answer:

The passenger aircraft would take 10.542 years to reach the Sun from the Earth.

The passenger aircraft would take $1.733\times 10^{10}$ years to reach the gallactic center.

Explanation:

The distance to the sun from the Earth is approximately equal to $1.496\times 10^{8}\,km$ , if the passenger travels at constant speed, then the time needed to reach the sun is calculated by the following kinematic formula:

$\Delta t = \frac{s}{v}$ (1)

Where:

$s$ - Travelled distance, measured in kilometers.

$v$ - Speed of the passenger aircraft, measured in kilometers per second.

$\Delta t$ - Travelling time, measured in seconds.

If we know that $s = 1.496\times 10^{8}\,km$ and $v = 0.45\,\frac{km}{s}$ , then the travelling time is:

$\Delta t = \frac{1.496\times 10^{8}\,km}{0.45\,\frac{km}{h} }$

$\Delta t = 3.324\times 10^{8}\,s$

$\Delta t = 3847.736\,days$

$\Delta t = 10.542\,years$

The passenger aircraft would take 10.542 years to reach the Sun from the Earth.

The distance between the Earth and the galactic center is approximately equal to $2.460\times 10^{17}\,km$ . If the passenger travels at constant speed and if we know that $s = 2.460\times 10^{17}\,km$ and $v = 0.45\,\frac{km}{s}$ , then the travelling time is:

$\Delta t = \frac{2.460\times 10^{17}\,km}{0.45\,\frac{km}{s} }$

$\Delta t = 5.467\times 10^{17}\,s$

$\Delta t = 6.327\times 10^{12}\,days$

$\Delta t = 1.733\times 10^{10}\,years$

The passenger aircraft would take $1.733\times 10^{10}$ years to reach the gallactic center.

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2 years ago