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4 years ago

What are the applications of electromagnetic waves

2 answers:

4 0

Answer:They are used to transmit short or long or FM wavelength radio waves. They are used to transmit TV or telephone or wireless signals and energies. They are responsible for the transmission of energy in the forms of microwaves, visible light, infrared radiation, ultraviolet light, gamma rays and also X-rays.

Explanation:

Serhud [2]4 years ago

4 0

-set the "atomic" clocks everywhere

-hear news & sports on AM radio

-low-band 2-way mobile radios ... fire, police, taxi, ambulance

-high-band 2-way mobile radios ... fire, police, taxi, ambulance

-over-the-air TV

-hear music on FM radio

-open the garage door while sitting in the car

-heat up leftover meatloaf in the 'microwave'

-cordless telephones in the house

-cellular telephones everywhere else

-all smartphone data, up and down, in and out

-GPS, and everything that uses it

-control & communicate with GPS satellites, weather satellites, TV satellites, military and government satellites, lunar orbiters, Hubble Space Telescope, the International Space Station, all interplanetary space probes

-everything Bluetooth

-everything Laser

-everything Microwave

-use eyes to see things

-use Infrared to heat things

-use ultraviolet to get a tan

-X-rays for dental and medical applications

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A particle moving along the x-axis has its velocity described by the function vx =2t2m/s, where t is in s. its initial position

Nesterboy [21]

The position of the object at time t =2.0 s is <u>6.4 m.</u>

Velocity vₓ of a body is the rate at which the position x of the object changes with time.

Therefore,

$v_x= \frac{dx}{dt}$

Write an equation for x.

$dx=v_xdt\\ x=\int v_xdt$

Substitute the equation for vₓ =2t² in the integral.

$x=\int v_xdt\\ =\int2t^2dt\\ =\frac{2t^3}{3} +C$

Here, the constant of integration is C and it is determined by applying initial conditions.

When t =0, x = 1. 1m

$x= \frac{2t^3}{3} +C\\ x_0=1.1\\ x= (\frac{2t^3}{3} +1.1)m$

Substitute 2.0s for t.

$x= (\frac{2t^3}{3} +1.1)m\\ =\frac{2(2.0)^3}{3} +1.1\\ =6.43 m$

The position of the particle at t =2.0 s is <u>6.4m</u>

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3 years ago

When you apply a horizontal force of 76 N to a block, the block moves across the floor at a constant speed ().When you apply a f

elena-s [515]

Answer:

Explanation:

When we apply a horizontal force of 76 N to a block, the block moves across the floor at a constant speed. So net force on the block is zero .

It implies that a force ( frictional ) acts on it which is equal to 76 N in opposite direction ( friction )

When we apply a greater force on it it starts moving with acceleration .

This time kinetic friction acts on it due to rough ground equal to 76 N .This is limiting friction ( maximum friction )

Net force on the body in later case

= 89 - 76

= 13 N

Force by ground on the block in horizontal direction = 76 N ( FRICTIONAL FORCE )

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4 years ago

If you fall from a building onto a net which extends the time of impact by 10 times, what happens to the force you experience?

zubka84 [21]

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A larger impulse. A 1-kg ball has twice as much speed as a 10-kg ball.

Explanation:

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3 years ago

How much energy to be removed to drop the temperature of 5.7kg of wood from 20degrees to 7degrees. #100points

Neporo4naja [7]

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3 years ago

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spin [16.1K]

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3 years ago

What are the applications of electromagnetic waves​

What are the applications of electromagnetic waves