Simplify x^2 + (y

denpristay [2]

The interior angles of a triangle equal 180°. To find y you do 180°-57-61 which equals 62. So the measure of angle y is 62°. You add 62 and 67 to get 129. Then you do 180 - 129 = 51. So the measure of angle x is 51°

4 0

3 years ago

Solve the inequality both algebraically and graphically. Draw a number line graph of the solution and give interval notation.

Lemur [1.5K]

Finding the solution algebraically

To answer this inequality, we can follow the next steps:

1. Multiply by 7 both sides of the inequality:

$7\cdot\frac{(x-7)}{2}$

2. Multiply by 2 both sides of the inequality:

$7\cdot2\cdot^{\cdot}\frac{(x-7)}{2}$

3. Apply the distributive property at the left side of the inequality:

$7\cdot x-7\cdot7$

4. Add 49 to both sides of the inequality:

$7x-49+49$

5. Finally, divide both sides of the inequality by 7:

$\frac{7x}{7}$

We can graph this inequality in the number line as follows:

Notice the parenthesis indicating that the solution is the number below 131/7 (but not equal to 131/7). In interval notation the solution is:

$(-\infty,\frac{131}{7})$ $(-\infty,18\frac{5}{7})$

Or, approximately:

$(-\infty,18.7142857143)$

The number 131/7 in decimal is equivalent to 18.7142857143, so the graph of the solution is given by graph A (we can see that there are seven divisions between 18 and 19; since we have that the shaded division is in the 5th division, then, we have 5/7 = 0.714285714286, that is, the decimal part of the above number).

We can express the number 131/7 as a mixed number as follows:

$\frac{131}{7}=\frac{126}{7}+\frac{5}{7}=18+\frac{5}{7}=18\frac{5}{7}$

Again, notice also the symbol for the left part of the interval notation is a parenthesis since the interval is open at the point 131/7 = 18 + 5/7.

Finding the solution graphically

To find the solution graphically, we can represent the inequality as two lines as follows:

$y=\frac{x-7}{2},y=\frac{41}{7}$

Then, if we graph the first line, we can find the x- and the y-intercepts to find two points to graph the line. We have that the x- and the y-intercepts are:

The x-intercept is (that is, when y = 0):

$0=\frac{x-7}{2}\Rightarrow x-7=0\Rightarrow x=7$

Then, the x-intercept is (7, 0), and the y-intercept (the point on the graph when x = 0) is:

$y=\frac{x-7}{2}\Rightarrow y=\frac{0-7}{2}\Rightarrow y=-\frac{7}{2}$

Then, the y-intercept is (0, -7/2).

The other line is given by:

$y=\frac{41}{7}=\frac{35}{7}+\frac{6}{7}=5\frac{6}{7}$

With this information, we can graph both lines:

And we can see that the point where the two lines coincide is:

$(\frac{131}{7},\frac{41}{7})$

Then, the values for x of the line (x-7)/2 [that is, the values of y = (x-7)/2] that are less than y = 41/7, represented as:

$\frac{(x-7)}{2}$

Are those values of x less than 131/7, or the solution is also (we express the solution as a fraction or a mixed number as follows) (the same solution):