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Afina-wow [57]
4 years ago
11

a box of rice cakes cost 1.95 what ia the greatest number of boxes of rice cakes jared can buy with $10

Mathematics
2 answers:
lapo4ka [179]4 years ago
5 0
Divide $10 by $1.95, and you should get approximately 5 boxes.
ikadub [295]4 years ago
3 0
5 boxes of rice cakes. It would cost him $9.75, so he would have 25 cents left over.
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The perimeter of the rectangle below is 94 units. Find the length of side BC.
Ilya [14]

Answer:

Length BC = 26

Step-by-step explanation:

Perimetre = 94

; Perimetre = 2(2x + 3) + 2(3x - 1)

; 94 = 4x + 6 + 6x - 2

; 94 - 4 = 10x

; 90 = 10x

;Therefore the value of x = 9....Hence the length of BC

BC = 3(9) - 1

; BC = 26

7 0
3 years ago
I need help please I don’t know what to do
Aleksandr-060686 [28]

Answer:

Your answer will be 5

Step-by-step explanation:

If the area is two sides multiplied by each other and its a square then all the sides are the same so take 5*5 and you get 25

4 0
4 years ago
Read 2 more answers
Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065. New equipment is being
Ilya [14]

Answer:

Yes, the new equipment appear to be effective in reducing the variation of​ weights.

Step-by-step explanation:

We are given that Quarters are currently minted with weights normally distributed and having a standard deviation of 0.065.

A simple random sample of 25 quarters is obtained from those manufactured with the new​ equipment, and this sample has a standard deviation of 0.047.

Let \sigma = <u><em>standard deviation of weights of new equipment.</em></u>

SO, Null Hypothesis, H_0 : \sigma \geq 0.065      {means that the new equipment have weights with a standard deviation more than or equal to 0.065}

Alternate Hypothesis, H_A : \sigma < 0.065      {means that the new equipment have weights with a standard deviation less than 0.065}

The test statistics that would be used here <u>One-sample chi-square</u> test statistics;

                           T.S. =  \frac{(n-1)s^{2} }{\sigma^{2} }  ~ \chi^{2}__n_-_1

where, s = sample standard deviation = 0.047

           n = sample of quarters = 25

So, <u><em>the test statistics</em></u>  =  \frac{(25-1)\times 0.047^{2} }{0.065^{2} }  ~  \chi^{2}__2_4   

                                     =  12.55

The value of chi-square test statistics is 12.55.

Now, at 0.05 significance level the chi-square table gives critical value of 13.85 at 24 degree of freedom for left-tailed test.

Since our test statistic is less than the critical value of chi-square as 12.55 < 13.85, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that the new equipment have weights with a standard deviation less than 0.065.

5 0
3 years ago
Y varies directly as x.x= 1/2 and y= 5/4. Find x when y= 10.<br> x= ?
Marta_Voda [28]

Answer:

<h2>X=4</h2>

Step-by-step explanation:

x=1/2=2/4

y=5/4

y=2.5x

10/2.5=4

so x=4

5 0
3 years ago
Fill in the table using this function rule<br><br> Y=2x+2
Flura [38]
10 12 18 20    
this is to hit 20 characters
6 0
4 years ago
Read 2 more answers
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