<span>Find the equation of the line parallel to the line y = 4x – 2 that passes through the point (–1, 5).
</span>y = 4x – 2 has slope = 4
<span>parallel lines have same slope so slope = 4
</span><span>passes through the point (–1, 5).
</span><span>y = mx+b
5 = 4(-1) + b
b =9
equation
y = 4x + 9
answer
The slope of y = 4x – 2 is 4
The slope of a line parallel to y = 4x – 2 is 4
The equation of the line parallel to y = 4x – 2 that passes through the point (–1, 5) is y = 4x + 9</span>
I get the base to be 4.74 and the height to be 12.74
Answer:
Step-by-step explanation:
![Hence,\\As\ Angle\ A\ and\ Angle\ B\ are\ co-interior\ angles, if\ they\ are\\ supplementary\ then\ AD \parallel BC.\ Lets\ check\ that\ out.\\Hence,\\Angle\ A=2x=2*15=30\\Angle\ B=90\ [Given]\\Hence,\\As\ 90+30\neq 180,\\Angle\ A +Angle\ B\neq 180\\Hence,\\As\ Angle\ A and\ Angle\ B\ are\ not\ supplementary, AD\ will\ not\ be\ parallel\ to\ CB.](https://tex.z-dn.net/?f=Hence%2C%5C%5CAs%5C%20Angle%5C%20A%5C%20and%5C%20Angle%5C%20B%5C%20are%5C%20co-interior%5C%20angles%2C%20if%5C%20they%5C%20are%5C%5C%20supplementary%5C%20then%5C%20AD%20%5Cparallel%20BC.%5C%20Lets%5C%20check%5C%20that%5C%20out.%5C%5CHence%2C%5C%5CAngle%5C%20A%3D2x%3D2%2A15%3D30%5C%5CAngle%5C%20B%3D90%5C%20%5BGiven%5D%5C%5CHence%2C%5C%5CAs%5C%2090%2B30%5Cneq%20180%2C%5C%5CAngle%5C%20A%20%2BAngle%5C%20B%5Cneq%20180%5C%5CHence%2C%5C%5CAs%5C%20Angle%5C%20A%20and%5C%20Angle%5C%20B%5C%20are%5C%20not%5C%20supplementary%2C%20%20AD%5C%20will%5C%20not%5C%20be%5C%20parallel%5C%20to%5C%20CB.)
"A" is the correct answer
