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melomori [17]
3 years ago
10

if the movie theater seats 328 people, what is the max amount of money the theater can bring in during a showing

Mathematics
1 answer:
alekssr [168]3 years ago
5 0

How much are each of the tickets?
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Please help I Think I'm wrong!!!!
Allisa [31]
2n+2(n-4)=56
2n+2n-8=56
4n-8=56
4n=64
n=16

1st side is 16
2nd side is 12
8 0
4 years ago
Assume V and W are​ finite-dimensional vector spaces and T is a linear transformation from V to​ W, T: Upper V right arrow Upper
scZoUnD [109]

Answer:

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

Step-by-step explanation:

Let B = {v_1 ,v_2,..., v_p} be a basis of H, that is dim H = p and for any v ∈ H there are scalars c_1 , c_2, c_p, such that v = c_1*v_1 + c_2*v_2 +....+ C_p*V_p It follows that  

T(v) = T(c_1*v_1 + c_2v_2 + ••• + c_pV_p) = c_1T(v_1) +c_2T(v_2) + c_pT(v_p)

so T(H) is spanned by p vectors T(v_1),T(v_2), T(v_p). It is enough to prove that these vectors are linearly independent. It will imply that the vectors form a basis of T(H), and thus dim T(H) = p = dim H.  

Assume in contrary that T(v_1 ), T(v_2), T(v_p) are linearly dependent, that is there are scalars c_1, c_2, c_p not all zeros, such that  

c_1T(v_1) + c_2T(v_2) +.... + c_pT(v_p) = 0

T(c_1v_1) + T(c_2v_2) +.... + T(c_pv_p) = 0

T(c_1v_1+ c_2v_2 ... c_pv_p) = 0  

But also T(0) = 0 and since T is one-to-one, it follows that c_1v_1 + c_2v_2 +.... + c_pv_p = O.

Thus for the vectors v_1, v_2, v_p there are scalars c_1, c_2, c_p not all zeros, such that c_1v_1 +c_2v_2+... +c_pv_p = 0. It means that the vectors v_1, v_2, v_p are linearly dependent in contradiction with the fact that the vectors form a basis for H. So the assumption that T(v_1), T(v_2),..., T(v_p) are linearly dependent is false, proving the required.  

8 0
3 years ago
Select the correct answer from each drop-down menu. Right triangle ABC is represented with the right angle at vertex B. Base BC
Svetradugi [14.3K]

By using trigonometric relations, we will see that:

AC = 15.6 in

AB = 8.4 in.

<h3>How to get the measures of the other two sides of the right triangle?</h3>

Here we have the right triangle where:

B = 90°

C = 40°

BC = 10 in.

Notice that is the adjacent cathetus to the angle C, then we can use the two relations:

  • sin(a) = (adjacent cathetus)/(hypotenuse).
  • tan(a) = (opposite cathetus)/(adjacent cathetus).

Where:

  • hypotenuse = AC
  • opposite cathetus = AB.

Then we will have:

sin(40°) = 10in/AC.

AC = 10in/sin(40°) = 15.6 in

tan(40°) = AB/10in

tan(40°)*10in = AB = 8.4 in.

So we can conclude that for the given right triangle we have:

AC = 15.6 in

AB = 8.4 in.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

6 0
2 years ago
Solve the radical equation. m - 3 = √ 19 - 3m. Which is an extraneous solution to the radical equation?
Sphinxa [80]
The answer is m=5 and m=-2. There is no extraneous solution for this equation.

7 0
4 years ago
Read 2 more answers
The ratio of the measure of the sides of the triangle is 1/6: 1/3: 1/4 if the perimeter of the triangle is 13.5 inches find the
marissa [1.9K]

Answer:

The shortest side of the triangle is 3 inches.

Step-by-step explanation:

Given:

The ratio of the measure of the sides of the triangle is 1/6: 1/3: 1/4.

The perimeter = 13.5 inches.

Now, to find the shortest side.

<em>Let the one side be \frac{1}{6}x</em>

<em>And the second side be  \frac{1}{3}x.</em>

<em>And the third side be  \frac{1}{4}x.</em>

According to question:

\frac{1}{6}x+\frac{1}{3}x+\frac{1}{4}x=13.5

⇒\frac{x}{6}+\frac{x}{3}+\frac{x}{4}=13.5

Adding all the variables by taking common denominator we get:

⇒\frac{9x}{12}=13.5

<em>Multiplying both sides by 12 we get</em>:

⇒9x=162

<em>Dividing both sides by 9 we get</em>:

⇒x=18

Thus, <em>the sides of the triangle are</em>:

<u>1/6×18=3 inches.</u>

<u>1/3×18=6 inches.</u>

<u>1/4×18=9/2=4.5 inches</u>.

Therefore, the shortest side of the triangle is 3 inches.

4 0
3 years ago
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