A frame-shift mutation would occur. This is because a
deletion will cause a change in codon sequence from the point of mutation to
the end of the mRNA. If the mutation is
closer to the start of the mRNA, the larger the effect of the mutation on the
translated protein.
The probability of long hair is 50%. The probability of short hair is also 50%. So, the probability of one of their offspring having long hair is 50%
Answer:
1. G° = -RT ln (G1P/P)
3.1 = 8.314 × 310 × ln (G1P/P)
3.1 / 2577.34 = ln (G1P/P)
0.0012 = ln (G1P/P)
0.0012 = (log G1P/P)/log 2.71828
0.4342 × 0.0012 = log G1P/P
0.00052 = log G1P/P
G1P/P = 10^0.00052 = 1.0012
P/G1P = 1/1.0012 = 0.9988
2. The cleavage of glycogen phosphorolytically is beneficial for the cell to conduct the process as the discharged glucose is phosphorylated. A general hydrolytic cleavage would give rise to only a glucose, which has to be phosphorylated again with the help of ATP.
Another merit of phosphorylated glucose is that it comprises the negative charge and cannot diffuse out of the muscle cell. Thus, the reaction will not be at equilibrium under the physiological conditions and always encourages the generation of the products. The formation of products will amend the change in free energy in such a manner that the reaction will always carry in the forward direction.
3. Greater the ratio of [Pi]/[glucose-1-phosphate], higher will be the relative rate of glycogen phosphorylase in comparison to the phosphoglucomutase as the transformation of Glu-1-P becomes slow because of lesser accessibility of substrate.
<em>Do not pick the other answer, it is incorrect!</em>
The correct answer is:
Cyst
Answer:
it addresses Loss of Biodiversity
Explanation:
if you read the question you find a key word which is decrease
hope this helped
