All categories

3 years ago

What is the value of y? 3 4 5 6

Mathematics

2 answers:

yawa3891 [41]3 years ago

7 0

Since the length of the side labeled 10 and the other side labeled 2y +4 are the same. Set them equal to each other and subtract 4 to the other side and then divide 2 to other side to get y=3. Your welcome.

pentagon [3]3 years ago

4 0

Answer:

It’s 3

Step-by-step explanation:

multiply 3 time 2 and add 4

You might be interested in

I need a help please

Lostsunrise [7]

Answer:

1)12 2) $a_{n}= a_{n+6}$

Step-by-step explanation:

Problem 1:

a(5)=25 a(3)=13

a(5)-a(3)=25-13=12

mark brainliest

5 0

2 years ago

Find the sum of the first 3 terms in the geometric sequence when the first term is 12 and the common ratio is 0.2

fgiga [73]

0.1000 but yeah because that is the only way to meausre so yeah hope i help lol

5 0

2 years ago

Solve the equation. Check your solution.4v÷27=16

svet-max [94.6K]

V=108 because 4 ÷ 16 = 4 then you have v ÷ 27 = 4 and 27 times for is 108

3 0

3 years ago

Read 2 more answers

A ball is thrown into the air. The path it takes is modeled by the equation: -3t+24t = h, where t is the time in seconds and h i

astra-53 [7]

Given:

The given equation is:

$-3t^2+24t=h$

Where, t is the time in seconds and h is the height of the ball above the ground, measured in feet.

To find:

The inequality to model when the height of the ball is at least 36 feet above the ground. Then find time taken by ball to reach at or above 36 feet.

Solution:

We have,

$-3t^2+24t=h$

The height of the ball is at least 36 feet above the ground. It means $h\geq 36$ .

$-3t^2+24t\geq 36$

$-3t^2+24t-36\geq 0$

$-3(t^2-8t+12)\geq 0$

Splitting the middle term, we get

$-3(t^2-6t-2t+12)\geq 0$

$-3(t(t-6)-2(t-6))\geq 0$

$-3(t-2)(t-6)\geq 0$

The critical points are:

$-3(t-2)(t-6)=0$

$t=2,6$

These two points divide the number line in 3 intervals $(-\infty,2),(2,6),(6,\infty)$ .

Intervals Check point $-3(t-2)(t-6)\geq 0$ Result

$(-\infty,2)$ 0 $(-)(-)(-)=(-)$ False

$(2,6)$ 4 $(-)(+)(-)=+>0$ True

$(6,\infty)$ 8 $(-)(+)(+)=(-)$ False

The inequality is true for (2,6) and the sign of inequality is $\geq$ . So, the ball is above 36 feet between 2 to 6 seconds.

$6-2=4$

Therefore, the required inequality is $-3t^2+24t\geq 36$ and the ball is 36 feet above for 4 seconds.

3 0

3 years ago

In a circle, a 90° sector has area 16π ft2. What is the radius of the circle?

Veronika [31]

Sector area = 0.5 * r^2 * angle (in radians)

so:

16 pi = 0.5 * r^2 * (90*pi/180)

r^2 = 16 pi /(0.25 pi) = 64

r = 8

therefore it would be d

7 0

2 years ago