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2 years ago

Jewelry marked 18- karat gold is 75% pure gold. How much pure gold is in an 18-karat gold necklace that weighs 258 grams

Mathematics

1 answer:

mihalych1998 [28]2 years ago

8 0

Answer:

The weight of pure gold in 258 g rams of 18- karat gold is 193.5 grams.

Step-by-step explanation:

The pure percentage in the gold = 75%

The weight of the gold purchased = 258 g

Now, here the pure gold percentage is 75% of 258 g

75% of 258 grams = $\frac{75}{100} \times 258$

or, $\frac{3}{4} \times 258 = 193.5$

⇒75% of 258 grams = 193.5 grams

Hence, the weight of pure gold in 258 g rams of 18- karat gold is 193.5 grams.

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Step-by-step explanation:

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The diagonal length of a rectangular playing field is 76 feet, and its width is 48 feet. How long is the playing field?

Sauron [17]

The length of playing field is 58.9 feet

Solution:

Given that, the diagonal length of a rectangular playing field is 76 feet,

And its width is 48 feet.

To find: length of playing field

Now, we know that, diagonal, width and length of a rectangle will form an right angle triangle with diagonal as hypotenuse.

So, now, in a right angled triangle we can use pythagorean theorem to find the length

Pythagorean theorem, states that the square of the length of the hypotenuse is equal to the sum of squares of the lengths of other two sides of the right-angled triangle.

By above definition, In a right angled triangle ABC we get

$c^2 = a^2 + b^2$

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"a" is the length of one leg of right angled triangle

"b" is the length of other leg of right angled triangle

$\begin{array}{l}{\text {Then, diagonal = width }^{2}+\text { length }^{2}} \\\\ {76^{2}=48^{2}+\text {length }^{2}} \\\\ {\text {Length }^{2}=76^{2}-48^{2}} \\\\ {\text {Length }^{2}=5776-2304}\end{array}$