Total = Principal * (1 + rate)^years
Total = 3,300 * (1.018)^5
Total = 3,300 *
<span>
<span>
<span>
1.0932988468
</span>
</span>
</span>
Total =
<span>
<span>
<span>
3,607.8</span></span></span>9
<h3>The worth after 4 years is $ 680.24</h3>
<em><u>Solution:</u></em>
<em><u>The formula for compound interest, including principal sum, is:</u></em>
Where,
A = the future value of the investment
P = the principal investment amount
r = the annual interest rate (decimal)
n = the number of times that interest is compounded per unit t
t = the time the money is invested
From given,
n = 1 ( since interest is compounded annually)
p = 500
t = 4
<em><u>Substituting the values we get,</u></em>
Thus the worth after 4 years is $ 680.24
Answer:
See below.
Step-by-step explanation:
1) Please check the number of volume of steel. It should be 54,259.2
. Not 54,259.2 cm. Right?
2) If so,
First
The volume of single rod
The number of rods
Answer:
[-4,0) ∪ [2, ∞)
Step-by-step explanation:
For piecewise function domain and range, we need to understand the difference between "(" and "[" or ")" and "]"
- The parenthesis ( "(" and ")" ) are used for "open circles" in the graph.
- The brackets ( "[" and "]" ) are use for "closed circles" in the graph.
Range is the set of y-values for which the function is defined.
Now,
The upper part of the function shows the graph going from y = 2 towards infinity (arrow). At y = 2 , there is closed circle, so this part range would be
[2, ∞) (infinity is always with parenthesis)
Now, looking at bottom part, the function is defined from 0 (open circle) to -4 (closed). so we can write:
[-4,0)
This is the range, 2nd answer choice is correct.
[-4,0) ∪ [2, ∞)
