Answer:
,
,
Step-by-step explanation:
In the case of parametric equations, the slope of the curve is equal to:
Where and are the first derivatives of and regarding . Let be and , their first derivatives are found:
and
Thus, equation for the slope is:
If , then:
Tangent is positive at 1st quadrant and is a function with a periodicity of , the set of solutions are:
,
,
Since both equations are equal to y, we can just combine them like this:
1/3x-3=-x+5
1/3x=-x+8
4/3x=8 (since x is 1x which is 3/3x)
x=6
Plug x back in:
y=-6+5
y=-1
So x=6 and y=-1
Hope this helped!
Answer: Hey, you need to add a photo, once you do so I will edit my answer
Answer:
C. ASA Similarity
Step-by-step explanation:
Using the Angle-Side-Angle Similarity Theorem is the only thing we can do because looking above we see that we know two angles and one side. Hence, this can be the only theorem that is fit for these two triangles.
The answer is D.
First solve for y.
You end up with:
y=-1/2x+3/2
Because they want a parallel line, the slope stays the same.
Our equation will look like
y=-1/2x+b
Now plug in the given coordinates
4=-1/2(6) + b
4=-3+b
b=7
Therefore, the equation of the line is
y = -1/2x + 7