(Pts: 1) Please help me! Question is in attachment!

Mathematics

2 answers:

Sloan [31]3 years ago

8 0

- - Solve:

To find the volume of a sphere:
$\frac{4}{3} *3.14*R^3$

3.14≈π

Now since its telling us to use π, then we do our formula by multiplying by π.

π=3.14 (Approximate amount)

So:

$4/3*3.14*9^3=3052.08$

So you are correct.

When Radius=9, you plug in for R. :)

zvonat [6]3 years ago

3 0

Yes your answer is correct.
9 = R , for radious
Sphere Formula = s = 4, Pi r powered by 2 , volume below :

Volume of a sphere = V = (4/3)x(3.14)x(r^3)

now we have to multiply by pi = 3.14 which gets us
3052.08 | in powered by 3

so again yes you were right

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8. Is the following statement true or false? Justify your conclusion. If a and b are nonnegative real numbers and a + b =0, then

atroni [7]

Answer:

If $a + b = 0$ then $a = 0$ and $b =0$

a | b | a + b (answer)

0 | 0 | 0

0 | 1 | 1

0 | 2 | 2

1 | 0 | 1

2 | 0 | 2

1 | 1 | 2

2 | 1 | 3

Step-by-step explanation:

Considering the following conditions for the real numbers:

$a\geq 0\\b\geq 0$

Following the rules of these in-equations, it is possible to deduce:

$a + b \geq 0$

Then, if the proposed statement is:

$a + b = 0$

The conditions above shall comply the requirements established, but first, analyzing the statement:

If $a \geq 0$ and $b \geq 0$ then $a + b \geq a$ , $a + b \geq b$ and $a + b \geq 0$ .

If $a = 0$ and b a non negative real number, then $a + b \geq b$ , but because to $a = 0$ , then $a + b = b$ . Due to the commutative property of sums, the same behavior will be presented if $b = 0$ and a a non negative real number.