Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
Answer:
16 + 3n
Step-by-step explanation:
a = 19 ; common difference = 22 - 19 = 3
a(n) = a + (n -1 ) *d
= 19 + (n-1)*3
= 19 + 3n - 3
= 16 + 3n
Answer:
7/12
Step-by-step explanation:
Basically to find the boys fraction I subtracted 40 from 96 and got 56. Your answer for the number of boys would be 56/96. I divided 4 from each and got 14/24. lastly I divide by 2 and got 7/12.
1 pound = 16 ounces
3 pounds = 3*16 ounces
3 pounds= 48 ounces
So, he can make 48 one-ounce bags
Answer:
I think it's six
Step-by-step explanation:
A= 1
b= 2
c= 3
