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2 years ago

Pls help . i have no clue how to do it

Mathematics

1 answer:

attashe74 [19]2 years ago

6 0

Answer:

Angle A is 53 degrees

Step-by-step explanation:

"Squaring the circle" with AC and CD makes Angle C 90 degrees. Since all triangles have their degrees total to 180 degrees 37+90=127

180-127=53

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The length of the missing side is: ?m

victus00 [196]

Answer:

85 ft

Step-by-step explanation:

for all right triangles, triangles with a 90 degree angle, the sides are equal to $a^{2} + b^{2} = c^{2}$ where c is the hypotenuse, or the longest side.

so... $40^{2} + 75^{2} = c^{2}$

$7225 = c^{2}$

c= 85

6 0

2 years ago

Solve for b. Round your answer to the nearest whole degree.

Talja [164]

Answer:

44°

Step-by-step explanation:

From sin rule:

a / sin A = b / sin B = c / Sin C

3.6 / sin b = 5.1 / sin 100

Cross multiply :

5.1 * sinb = 3.6 * sin 100

Sin b = 3.5453079 / 5.1

Sin b = 0.6951584

b = sin^-1(0.6951584)

b = 44.039

b = 44°

8 0

2 years ago

Solve for x: −10x+5= -6x-35

Makovka662 [10]

X= 10 I did it on my calculator so don’t worry :)

5 0

2 years ago

Read 2 more answers

Use the parabola tool to graph the quadratic function f (x) = 2x2 - 4x + 6.

lubasha [3.4K]

Answer:

Vertex plot is (1,4)

and

second plot point (0,6)

Step-by-step explanation:

You can use the the desmos graph calculator by entering quadratic function f(x) = 2x^2 − 4x + 6

3 0

2 years ago

I need help with this ASAP plzzzzz

miss Akunina [59]

Answer:

23. $\frac{4\sqrt{3} }{3}$

24. $\frac{7\sqrt{3}}{3}$

25. $6\sqrt{3}$

26. $\frac{10\sqrt{3} }{3}$

27. $14$

28. $4\sqrt{3}$

Step-by-step explanation:

To solve these i used SOHCAHTOA

$sin=\frac{opposite}{adjacent}\\ cos=\frac{adjacent}{hypotenuse} \\tan=\frac{opposite}{adjacent}$

23.

Find the missing side using Tangent

$tan(30)=\frac{x}{4}$

$4*tan(30)=x$

$\frac{4\sqrt{3} }{3}$

24.

Find the missing side using Tangent

$tan(30)=\frac{x}{7}$

$7*tan(30)=x$

$\frac{7\sqrt{3}}{3}$

25.

Find the missing side using Tangent

$tan(30)=\frac{x}{18}$

$18*tan(30)=x$

$6\sqrt{3}$

26.

Find the missing side using Tangent

$tan(30)=\frac{x}{10}$

$10*tan(30)=x$

$\frac{10\sqrt{3} }{3}$

27.

Find the missing side using Tangent

$tan(30)=\frac{x}{14\sqrt{3} }$

$(14\sqrt{3}) *tan(30)=x$

$14$

28.

Find the missing side using Tangent

$tan(30)=\frac{x}{12}$

$12*tan(30)=x$

$4\sqrt{3}$

5 0

3 years ago