Given: Sound Intensity ( I ) = 
We know, the approximate threshold of human hearing is at 1kHz. In watts/m^2 it's value is
⁻¹² W/m².
So, we can say, Reference sound intensity
= 10⁻¹² W/m².
We have formula for "sound intensity level LI in dB" when entering sound intensity.
LI = 10×log (I / Io) in dB
Plugging values of I and Io in formula.
LI = 10 × log (
)
LI = 10 × log (99000000)
= 10 × 7.99564
LI = 79.96 dB.
Therefore, 79.96 dB is the sound level for a noise that has an intensity of 9.9 × 10-5 watts/m2.
Answer:
$15.50
Step-by-step explanation:
The total she spent was $28.50 ($18.00 purse and $10.50 wallet).
The amount she would have spent is $44 ($30+$14).
$44 - $28.50= $15.50 was saved.
I thought it was -4 I calculated it and that’s what I got?¿