Identify two prime numbers that are greater than 25 and less than 35

1 answer:

4 0

So sorry if I didn't answer sooner, but you want to know what a prime number is right? I assume you now, but notice a small pattern, notice how most number 7's are prime right? 17, 27, 37 except for 11*7 of course. So 27 is one, then three is the same except 33. So try those out.

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I need to what (0.3) to the 6th power =[1] is when calculated.

eduard

0.3=3/10

(3/10)^6
=3^6/10^6
=729/1000000
=0.000729

6 0

3 years ago

WHAT IS A VOLUME OF THE BOX WITH A HEIGHT OF 3\2 WIDTH OF 5\2 AND LENGHT OF 7\2

Vlad1618 [11]

Answer:

13.125 or 105/8u^3

Step-by-step explanation:

To find the volume of the box, you can use the formula of length times width time height.

3 * 5 = 15

2*2=4

15/4*7/2=105/8 which can be divided to become 13.125

7 0

3 years ago

I need help in partial fraction!! With simple explaination would be nice!

WITCHER [35]

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}$

The degree of the numerator (4) is larger than the degree of the denominator (3), so first you need to divide. (Added screenshot of long division procedure.)

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x-\dfrac{4x^2-17x+10}{x(x^2-3)}$

Now the second term can be decomposed into partial fractions.

$\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1}x+\dfrac{r_2x+r_3}{x^2-3}$
$\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1(x^2-3)+x(r_2x+r_3)}{x(x^2-3)}$
$4x^2-17x+10=r_1(x^2-3)+x(r_2x+r_3)$
$4x^2-17x+10=(r_1+r_2)x^2+r_3x-3r_1$
$\implies\begin{cases}r_1+r_2=4\\r_3=-17\\-3r_1=10\end{cases}\implies r_1=-\dfrac{10}3,r_2=\dfrac{22}3,r_3=-17=-\dfrac{51}3$
$\implies\dfrac{4x^2-17x+10}{x(x^2-3)}=-\dfrac{10}{3x}+\dfrac{22x-51}{x^2-3}$

So

$\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x+\dfrac{10}{3x}-\dfrac{22x-51}{x^2-3}$