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Bad White [126]

3 years ago

5

The total age of a woman and her son is 51 years. Three years ago, the woman was eight times as old as her son. How is old is he

r son now?
Algebra question

1 answer:

Veronika [31]3 years ago

6 0

51 - 3 = 48

48 / 8 = 6

6 + 3 = 9

Her son is 9 years old

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Tim earns $280 every week in his paycheck. If he saves 10% of each

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Answer:

336

Step-by-step explanation:

10 times 280 over 100 equals 28 time 12 equals 336

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3 years ago

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marusya05 [52]

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago

If x square plus 8x plus q =(x plus k) Square find the value of k and q

PIT_PIT [208]

Answer:

The value of k is 4 and q is 16.

Step-by-step explanation:

First, you have to expand the brackets by applying :

${(a + b)}^{2} = {a}^{2} + 2ab + {b}^{2}$

${x}^{2} + 8x + q = {(x + k)}^{2}$

${x}^{2} + 8x + q = {x}^{2} + 2kx + {k}^{2}$

Next, you have to do it by comparison :

${x}^{2} + 8x + q = {x}^{2} + 2kx + {k}^{2}$

$by \: comparison$

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$q = 16$

7 0

3 years ago

Assume the upper arm length of males over 20 years old in the United States is approximately Normal with mean 39.2 centimeters (

MAVERICK [17]

Answer:

The interval [32.6 cm, 45.8 cm]

Step-by-step explanation:

According with the <em>68–95–99.7 rule for the Normal distribution:</em> If $\large \bar x$ is the mean of the distribution and s the standard deviation, around 68% of the data must fall in the interval

$\large [\bar x - s, \bar x +s]$

around 95% of the data must fall in the interval

$\large [\bar x -2s, \bar x +2s]$

around 99.7% of the data must fall in the interval

$\large [\bar x -3s, \bar x +3s]$

So, the range of lengths that covers almost all the data (99.7%) is the interval

[39.2 - 3*2.2, 39.2 + 3*2.2] = [32.6, 45.8]

<em>This means that if we measure the upper arm length of a male over 20 years old in the United States, the probability that the length is between 32.6 cm and 45.8 cm is 99.7%</em>

3 0

2 years ago