We are given with a equation of Circle and we need to find it's radius and it's equation in standard form . But , let's recall , the standard equation of a circle is where <em>(h,k)</em> is the centre of the circle and radius is <em>r</em> . Proceeding further ;
Collecting <em>x</em> terms , y terms and transposing the constant to RHS ;
Now , as in standard equation their is a whole square , so we need to develop a whole square in LHS , for which we will use completing the square method , as coefficient of x² and y² is 1 , so adding 121 and 36 to LHS and RHS .
On comparing this with the standard equation , we got our centre at <em>(-11,-6)</em> and radius is <em>18 units </em>