Question

If y=3/x then y'=?A)-y/xB)y/xC)-x/yD)-3x/yE)-y/3x

Answer 1

$y=\dfrac{3}{x}\\\\\\ y'=\left(\dfrac{3}{x}\right)'=(3\cdot x^{-1})'=3\cdot(x^{-1})'=3\cdot(-1)\cdot x^{-2}=-3\cdot x^{-2}=\\\\\\=-\dfrac{3}{x^2}=-\dfrac{3}{x\cdot x}=-\dfrac{3}{x}\cdot\dfrac{1}{x}=-y\cdot\dfrac{1}{x}=-\dfrac{y}{x}$

Answer (A)