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3 years ago

If y=3/x then y'=?A)-y/xB)y/xC)-x/yD)-3x/yE)-y/3x

Mathematics

1 answer:

Marina86 [1]3 years ago

4 0

$y=\dfrac{3}{x}\\\\\\
y'=\left(\dfrac{3}{x}\right)'=(3\cdot x^{-1})'=3\cdot(x^{-1})'=3\cdot(-1)\cdot x^{-2}=-3\cdot x^{-2}=\\\\\\=-\dfrac{3}{x^2}=-\dfrac{3}{x\cdot x}=-\dfrac{3}{x}\cdot\dfrac{1}{x}=-y\cdot\dfrac{1}{x}=-\dfrac{y}{x}$

Answer (A)

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