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Allisa [31]
4 years ago
9

Find the horizontal asymptote of f(x)=x^2+6x-8/x-8

Mathematics
2 answers:
IRINA_888 [86]4 years ago
8 0
Look at the definitiioin

OLEGan [10]4 years ago
7 0
1. If <span><span>n<m</span><span>n<m</span></span> , then the x-axis, <span><span>y=0</span><span>y=0</span></span>, is the horizontal asymptote.2. If <span><span>n=m</span><span>n=m</span></span> , then the horizontal asymptote is the line <span><span>y=<span>ab</span></span><span>y=<span>ab</span></span></span>.3. If <span><span>n>m</span><span>n>m</span></span>, then there is no horizontal asymptote (there is an oblique asymptote).<span><span><span><span><span>x2</span><span><span>−6</span>x</span></span>+8</span><span><span><span>x2</span><span>−x</span></span><span>−12</span></span></span><span><span><span><span>x2</span><span><span>-6</span>x</span></span>+8</span><span><span><span>x2</span><span>-x</span></span><span>-12</span></span></span></span>Find <span>nn</span> and <span>mm</span>.<span><span>n=2</span><span>n=2</span></span><span><span>m=2</span><span>m=2</span></span>Since <span><span>n=m</span><span>n=m</span></span>, the horizontal asymptote is the line <span><span>y=<span>ab</span></span><span>y=<span>ab</span></span></span> where <span><span>a=1</span><span>a=1</span></span> and <span><span>b=1</span><span>b=1</span></span>.<span><span>y=1</span><span>y=1</span></span>There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.No Oblique AsymptotesThis is the set of all asymptotes.Vertical Asymptotes: <span><span>x=<span>−3</span></span><span>x=<span>-3</span></span></span>Horizontal Asymptotes: <span>y=<span>1</span></span>
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