Question

Find the horizontal asymptote of f(x)=x^2+6x-8/x-8

Answer 1

Look at the definitiioin

Answer 2

1. If n<mn<m , then the x-axis, y=0y=0, is the horizontal asymptote.2. If n=mn=m , then the horizontal asymptote is the line y=aby=ab.3. If n>mn>m, then there is no horizontal asymptote (there is an oblique asymptote).x2−6x+8x2−x−12x2-6x+8x2-x-12Find nn and mm.n=2n=2m=2m=2Since n=mn=m, the horizontal asymptote is the line y=aby=ab where a=1a=1 and b=1b=1.y=1y=1There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.No Oblique AsymptotesThis is the set of all asymptotes.Vertical Asymptotes: x=−3x=-3Horizontal Asymptotes: y=1