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arsen [322]
3 years ago
11

Given this set of daily service operations, and assuming a processing order of A-B-C-D-E: Service Operation Number of Daily Reps

A 32 B 24 C 32 D 28 E 12 a. Give one reason that each arrangement might be preferred over the other. b. Determine the number of repetitions for each service if four cycles are used.c. Determine the number of repetitions for each service if two cycles are used.

Business
2 answers:
leonid [27]3 years ago
3 0

Answer:

A.Given this set of daily service operations, and assuming a processing order of A-B-C-D-E: Service Operation Number of Daily Reps A 32 B 24 C 32 D 28 E 12 a. Give one reason that each arrangement might be preferred over the other. b. Determine the number of repetitions for

B.

Step-1: Calculate the units to be processed in one cycle by dividing the daily requirement with number of cycles

Step-2: Assign units per cycle to each cycle

Step-3: Adjust it to accommodate the fractions

C.

Step-1: Calculate the units to be processed in one cycle by dividing the daily requirement with number of cycles,

Step-2: Assign units per cycle to each cycle

The repetitions for each service if two cycles

Explanation: tables in attached file are for questions B and C respectively

Zanzabum3 years ago
3 0

Answer:

Explanation:

(a) The reason why each arrangement might be preferred over the other depends on the operation plan. Bigger plan, bigger arrangement and vise versa.

(b)

The number of repetition is calculated in the table below

Service Operation    No. of daily reps      No. of cycles     Reps per cycle

A                                          32                          4                   32/4 =  8

B                                           24                          4                   24/4 = 6

C                                           32                          4                   32/4 = 8

D                                           28                          4                   28/4=  7

E                                            12                           4                   12/4= 3

The number of repetition per cycle can then be expressed as;

Service Operation    Cycle 1          Cycle 2            Cycle 3       Cycle 4

            A                        8                    8                        8                 8

            B                        6                    6                       6                 6

            C                        8                    8                       8                 8

            D                        7                    7                        7                 7

            E                         3                    3                       3                 3

(c) The same process is used with two cycles

Service Operation    No. of daily reps      No. of cycles     Reps per cycle

        A                                   32                          2                   32/2 =  16

        B                                   24                          2                   24/2 = 12

        C                                   32                          2                   32/2 = 16

        D                                   28                          2                   28/2=  14

        E                                    12                           2                   12/2=   6

The number of repetition per cycle can then be expressed as;

Service Operation              Cycle 1                      Cycle 2            

            A                                     16                            16                      

            B                                     12                            12                    

            C                                     16                            16                      

            D                                     14                            14                        

            E                                      6                             6                      

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