Answer: The equation of a line with a slope of 0 that passes through the point (6,-11) will be y = - 11
Step-by-step explanation:
We want to determine the equation of a line with a slope of 0 that passes through the point (6,-11)
Slope of the line = change in the value of y on the vertical axis / change in the value of x on the x axis.
Recall,
The the equation of a straight line is represented in the slope intercept form is
y = mx + c
Where
m = slope
c = intercept on the y axis
From the equation information given,
slope, m = 0
y = -11
x = 6
To get the intercept, c,
y = mx + c
-11 = 0 × x + c
-11 = c
c = -11
The equation of a line with a slope of 0 that passes through the point (6,-11) will be
y = 0x - 11
y = - 11
Direct variation is modeled by the equation y = kx, where k is a constant and x and y vary based on the other's value.
We'll first need to find k, also known as the constant of variation, using our given values of x and y.
6 = k * -7
k = -6/7
Now that we have k, we can plug it in and substitute other values in for x or y. In this case, we'll plug in 4 for x and solve for y.
y = -6/7x
y = -6/7 * (4)
y = -24/7
y = -24/7
Hope this helps!
The answer would be
y = 7x - 4
Answer:
it equals 14
Step-by-step explanation:
The answer would be 59 miliseconds
