Ask question

Ask question

All categories

3 years ago

10

How do I find the length of an Arch in a circle?

1 answer:

VladimirAG [237]3 years ago

6 0

The length of the arc of the sector and central angle are directly proportional to each other.
the circumference of that circle is 12 * pi(=3.14159265358979......) ft
central angle of the circle is 360
arc AB = 12 * {pi} * 120/360 ft
=4 {pi} ft

You might be interested in

I'm so confused and need help

siniylev [52]

Answer:

SAS, SSS, AAA

Step-by-step explanation:

Because Im bored X D

6 0

3 years ago

-3(-4b - 7n) use n = 8 and b = 2

gogolik [260]

The answer for your problem is 192

7 0

3 years ago

Help pls click on pic

Rama09 [41]

See attachment for math work and answer.

7 0

3 years ago

a cone with a radius of 3” has a total area of 24pie square inches. Find the volume of the cone. 12pie, 24 pie or 15 pie

Ratling [72]

Answer:

$12\pi (inches)^{2}$

Step-by-step explanation:

Given:

radius of cone = 3 inch

Total area of cone = $24\pi (inch)^{2}$

Find the volume of the cone?

We know the area of cone = $\pi r(r+s)$ -------(1)

Where r = radius

Ans s = side of the cone

Put the area value in equation 1

$24\pi=\pi r(r+s)$ -------(1)

$\frac{24\pi }{\pi r} =r+s$

$\frac{24}{ r}-r =s$

Put r value in above equation.

$s =\frac{24}{ 3}-3$

$s=8-3$

$s=5$

The side s = 5 inches

We know the side of the cone formula

$s^{2}=r^{2}+ h^{2}$

$h^{2}=s^{2}- r^{2}$

Put r and s value in above equation.

$h^{2}=5^{2}- 3^{2}$

$r^{2} = 25-9$

$r^{2} = 16$

$r = 4$

The volume of cone is

$V = \frac{1}{3} \pi r^{2} h$

Put r and h value in above equation.

$V = \frac{1}{3} \pi (3)^{2}\times 4$

$V = 12\pi (inches)^{2}$

The Volume of the cone is $12\pi (inches)^{2}$

7 0

3 years ago

What are the first and last deciles of the standard Normal distribution?

aliya0001 [1]

My best Guess is

1.282 for upper . , -1.282 for lower.

Hope this Helps

-Dante

5 0

3 years ago