The first step is to divide by four to both sides
Are the inequalities x > 3 and 3 < x equivalent?
They both say that x must be larger than 3. No bickering here. So yep, they're equivalent.
Inequalities usually have a lot of solutions—in fact, infinitely many. Think about the inequality x > 3. This inequality states that "x must be larger than 3." Any number bigger than 3 is a solution to this inequality. That includes 3.001, 3.0001, 4, 5, 2 million, and every other number bigger than 3. We don't have time at the moment to name them all,
Answer:
$6
Step-by-step explanation:
$20-$14=$6
Step-by-step explanation:
k=8 that is the equation with no solutions
The diagonal of a rectangle = sqrt(w^2 + l^2)
w = width
l = length
In this problem,
The diagonal = 20 in
w = x
l = 2x + 8
Let's plug our numbers into the formula above.
20in = sqrt((x)^2 + (2x + 8)^2)
Let's simplify the inside of the sqrt
20 in = sqrt(5x^2 + 32x + 64)
Now, let's square both sides.
400 = 5x^2 + 32x + 64
Subtract 400 from both sides.
0 = 5x^2 + 32x - 336
Factor
0 = (5x - 28)(x + 12)
Set both terms equal to zero and solve.
x + 12 = 0
Subtract 12 from both sides.
x = -12
5x - 28 = 0
Add 28 to both sides.
5x = 28
Divide both sides by 5
x = 28/5
The width cant be a negative number so now we know that the only real solution is 28/5
Let's plug 28/5 into our length equation.
Length = 2(28/5) + 8 = 56/5 + 8 = 96/5
In conclusion,
Length = 96/5 inches
Width = 28/5
