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3 years ago

Sara would like to open a bank account. What will she need to do this? Check all that apply.

Mathematics

1 answer:

Eduardwww [97]3 years ago

6 0

Answer:

1,3,5

Step-by-step explanation:

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Two consecutive even integers have a sum of 34. find the integers

poizon [28]

Answer: 16, 18

Step-by-step explanation:

16 + 18 = 34

3 0

3 years ago

The equations y = 30x + 10 and y = –x2 + 150x + 10 model the daily sales of two car models, where x represents the number of day

yuradex [85]

Answer:

day 0, day 120

Step-by-step explanation:

You want to find the value of x that makes both y-values be the same:

y = y

30x +10 = -x^2 +150x +10

x^2-120x = 0 . . . . subtract the right side of the equation

x(x -120) = 0 . . . . . factor

Values of x that make this true are x=0 and x=120.

The same number of each car was sold on day 0 and day 120.

7 0

3 years ago

Plz help I will mark you brainlist plz help

lakkis [162]

Answer

1.) 50 mistakes per test

2.) 8 girls per group

3.) 27 pages per hour

4.) $1.30 per banana

5.) $0.50 per pencils

6.) 13 points per game

7.) $1.25 per cup of tea

8.) 65 liters per hour

9.) 25 calls per hour

10.) 35 words per minute

11.) 8 miles per liter of gas

12.) 0.4 eggs per day

13.) $28 per hour

14.) 3.5 miles per hour

Step-by-step explanation:

*Hope this helped*

8 0

3 years ago

Read 2 more answers

Tisha and her academic team are working to go to state finals. They must have a certain number of points to advance. They have h

Westkost [7]

Answer:

b equals T minus a minus c minus d all over 3 ⇒ 3rd answer

Step-by-step explanation:

* Lets explain how to solve the problem

- Tisha and her academic team have had three local matches

# Assume that the points of the local matches are a , c , d

- They will attend a district match

- District match points count for three times the number of points

than local matches do

# Assume that the points of the district match is b

- T is the total points they will earned in the four matches

∵ The points in the local matches are a , c , d

∵ The point in district mach is 3b

∴ T = a + c + d + 3b

* Lets find b in terms of a , c , d , T

∵ T = a + c + d + 3b

- Subtract a from both sides

∴ T - a = c + d + 3b

- Subtract c from both sides

∴ T - a - c = d + 3b

- Subtract d from both sides

∴ T - a - c - d = 3b

- Divide both sides by 3

∴ $b=\frac{T-a-c-d}{3}$

∴ b equals T minus a minus c minus d all over 3

4 0

3 years ago

Read 2 more answers

i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.

Natali [406]

Answer:

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = -5\sqrt 2$

Step-by-step explanation:

Given

$N = (-7,-1)$ --- terminal side of $\varnothing$

Required

Determine the values of trigonometric functions of $\varnothing$ .

For $\varnothing$ , the trigonometry ratios are:

$sin\ \varnothing = \frac{y}{r}$ $cos\ \varnothing = \frac{x}{r}$ $tan\ \varnothing = \frac{y}{x}$

$cot\ \varnothing = \frac{x}{y}$ $sec\ \varnothing = \frac{r}{x}$ $csc\ \varnothing = \frac{r}{y}$

Where:

$r^2 = x^2 + y^2$

$r = \sqrt{x^2 + y^2$

In $N = (-7,-1)$

$x = -7$ and $y = -1$

So:

$r = \sqrt{(-7)^2 + (-1)^2$

$r = \sqrt{50$

$r = \sqrt{25 * 2$

$r = \sqrt{25} * \sqrt 2$

$r = 5 * \sqrt 2$

$r = 5 \sqrt 2$

Solving the trigonometry functions

$sin\ \varnothing = \frac{y}{r}$

$sin\ \varnothing = \frac{-1}{5\sqrt 2}$

Rationalize:

$sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$sin\ \varnothing = \frac{-\sqrt 2}{5*2}$

$sin\ \varnothing = \frac{-\sqrt 2}{10}$

$sin\ \varnothing = \frac{-1}{10}\sqrt 2$

$cos\ \varnothing = \frac{x}{r}$

$cos\ \varnothing = \frac{-7}{5\sqrt 2}$

Rationalize

$cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}$

$cos\ \varnothing = \frac{-7\sqrt 2}{10}$

$cos\ \varnothing = \frac{-7}{10}\sqrt 2$

$tan\ \varnothing = \frac{y}{x}$

$tan\ \varnothing = \frac{-1}{-7}$

$tan\ \varnothing = \frac{1}{7}$

$cot\ \varnothing = \frac{x}{y}$

$cot\ \varnothing = \frac{-7}{-1}$

$cot\ \varnothing = 7$

$sec\ \varnothing = \frac{r}{x}$

$sec\ \varnothing = \frac{5\sqrt 2}{-7}$

$sec\ \varnothing = \frac{-5}{7}\sqrt 2$

$csc\ \varnothing = \frac{r}{y}$

$csc\ \varnothing = \frac{5\sqrt 2}{-1}$

$csc\ \varnothing = -5\sqrt 2$

3 0

3 years ago