Answer:
3x^2y^2
Step-by-step explanation:
I think:
3*2*x*x*x*y*y*y*y
3*3*x*x*y*y
3*6*x*x*x*y*y
They all have 3x^2y^2 in common.
The tangent line to a curve is the one that coincides with the curve at a point and with the same derivative, that is, the same degree of variation.
We have then:
y = 5x-x²
Deriving:
y '= 5-2x
In point (1, 4)
The slope is:
y (1) '= 5-2 * (1)
y (1) '= 3
The equation of the line will be:
y-f (a) = f '(a) (x-a)
We have then:
y-4 = 3 (x-1)
Rewriting:
y = 3x-3 + 4
y = 3x + 1
Answer:
the tangent line to the parabola at the point (1, 4) is
y = 3x + 1
the slope m is
m = 3
10^1 = 10
10^2 = 100 {10 x 10 = 100}
10^3 = 1000 {10 x 10 x 10 = 1,000}
10^4 = 10000 {10 x 10 x 10 x 10 = 10,000}
The exponent represents how many zeros will be used in the answer. For example, 10^6 would include 6 zeros in it’s answer; 1,000,000.
Answer:
Step-by-step explanation:
This is a right triangle trig problem. The base of the right triangle is the distance that Donna if from the flagpole; the flagpole is the side opposite the reference angle which was given as 26, and we are looking for the height of the flagpole, h. The trig ratio that uses the side opposite over the side adjacent is the tangent ratio, specifically:
and
123tan(26) = h so
h = 60.0 rounded to the nearest tenth. But that is only the height from her line of vision and up, not the whole height. In order to find the whole height, we have to add in her height up to her line of vision which is 5.3 feet. Therefore, the height of the flagpole is
60.0 + 5.3 = 65.3 feet.