Answer:
Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not have a solution.
Create a single variable linear equation that has one solution. Solve the equation algebraically to prove that there is one distinct solution for the equation.
Create a single variable linear equation that has infinitely many solutions. Solve the equation algebraically to prove that there is an infinite number of solutions for the equation
Step-by-step explanation:
Answer:
this is your answers for
Step-by-step explanation:
8hrs and both equal
Answer:
True
Step-by-step explanation:
The null space of matrix is set of all solutions to matrix. The linearly independent vectors forms subset which are spanned and forms the null space. The null space of vector can be found by reducing its echelon. The non zero rows formed are the null spaces of matrix.
So you subtract, 27-22. 27-22 is equal to 5. So, John will buy 5 kinds of T- Shirts.
Answer:
y=-x-2
Step-by-step explanation:
y+5=-(x-3)
y+5=-x+3
y=-x+3-5
y=-x-2
