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qaws [65]
3 years ago
10

The polynomial x3+8 is equal too (x+2)(x2-2x+4

Mathematics
2 answers:
nekit [7.7K]3 years ago
8 0
For starters:  Please practice presenting polynomial expressions properly.

<span>x3+8 is equal too (x+2)(x2-2x+4  

should be written as   "x^3 + 8 is equal to (not too)  (x+2)(x^2 - 2x + 4).

You don't share the instructions.  I suspect you are to respond "true" or "false."

It happens that x^3 + 8 equals   x^3 + 2^3, which is the sum of two cubes.

There is a formula for the "sum of two cubes:" 

It is a^3+b^3 = (a^2 - ab + b^2)(a+b).

Therefore, </span>x^3 + 2^3 = (x+2)(x^2 -2x + 2^2), or (x+2)(x^2 - 2x + 4).
swat323 years ago
3 0
This is the sum of cubes which factors to:

(x+2)(x^2-2x+4)
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Sally is planning the school picnic and needs to decide what food vendor to use. She asks 250 students whether they would rather
Oksana_A [137]

Answer:

0.18

Step-by-step explanation:

The relative frequency of eight graders who want fruit smoothie :

Number of eight graders who want fruit smoothie / total number of students surveyed

= 45 / 250

= 0.18

6 0
3 years ago
PLEASE HELP!!!! 20 POINTS!!!!
galben [10]
These are two questions and two answers.

Question 1) Which of the following polar equations is equivalent to the parametric equations below? 

<span> x=t²
y=2t</span>

Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>

Explanation:

1) Polar coordinates ⇒ x = r cosθ and y = r sinθ

2) replace x and y in the parametric equations:

r cosθ = t²
r sinθ = 2t

3) work r sinθ = 2t

r sinθ/2 = t 
(r sinθ / 2)² = t²

4) equal both expressions for t²

r cos θ = (r sin θ / 2 )²

5) simplify

r cos θ = r² (sin θ)² / 4

4 = r (sinθ)² / cos θ

r = 4 cosθ / (sinθ)²

r = 4 cot θ csc θ ↔ which is the option A.


Question 2) Which polar equation is equivalent to the parametric equations below?

<span> x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>

Answer: option B) r = sinθ + 1


Explanation:

1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ

2) replace x and y in the parametric equations:

a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span> b) r sinθ =sin²(θ)+sin(θ)</span>

3) work both equations

a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1]  ⇒ r = sinθ + 1


<span> b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
6 0
3 years ago
Read 2 more answers
Gayle starts to save at age 20 for an extended vacation around the world that she will take on her 45th birthday. She will contr
Katen [24]
For this case we have the following equation:
 P (t) = P (1 + r / n) ^ (n * t)
 Where,
 P: initial investment
 r: interest
 n: periods
 t: time
 she will take on her 45th birthday:
 for t = 25:
 P (25) = 1000 * (1 + 0.0165 / 4) ^ (4 * 25)
 P (25) = 1509.31 $
 Answer:
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8 0
3 years ago
Read 2 more answers
For function of g,g(0)=1 and g(1)=5 assuming g is a linear function what is g(3)<br>​
lawyer [7]

Answer:

g(3) = 13

Step-by-step explanation:

Given

g(0) = 1

g(1) = 5

Required

Find g(3)

Since g(x) is a linear function, then:

g(x) = mx + c

For: g(0) = 1

g(x) = mx + c

g(0) = m*0 + c

1 = 0 + c

1 = c

c = 1

For: g(1) = 5

g(x) = mx + c

g(1) = m * 1 + c

5 = m * 1 + c

5 = m + c

Substitute c = 1

5 = m + 1

m = 5 - 1

m =4

So, the function is:

g(x) = mx + c

g(x) = 4x + 1

Calculate g(3)

g(3) = 4*3 + 1

g(3) = 12 + 1

g(3) = 13

3 0
3 years ago
What is the solution to 2sin^(2)x+sinx+1=0
Alexus [3.1K]
Well you can try rewriting it to this

answer is   d  270

first start of by factoring  and subtracting the 1 into the right side

sin(x)  ( 2 sin (x)  + 1)  = -1  

set each one equal to -1 

sin( x) = -1   and   2 sin (x) +1 =  -1 

                              2 sin (x) = -2
                               sin ( x) = -1 
so therefore we have our final equation

sin ( x )  = - 1  and sin (x) = -1 

so then you look in your unit circle and find what coordinate equals -1 in terms of sin x 

3 0
4 years ago
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