Solve the equation. –4y + 8 = 4(2y – 2) + 4(8 - 2y)

Mathematics

2 answers:

OleMash [197]3 years ago

8 0

Remove the brackets -4y+8=8y-8+32-8y
collect like terms
-4y+8y-8y=-8-8+32
-4y=16 divide both by -4
y=-4

ss7ja [257]3 years ago

4 0

-Y+2=(2y-2)+(8-2y) @
Y=-4

You might be interested in

Triangle X Y Z is shown. Line Z X is extended through point W to form exterior angle W X Y.

Y_Kistochka [10]

Answer:

C: m∠WXY + m∠YXZ = 180°

Step-by-step explanation:

edu is annoying to do, i got you :)

4 0

3 years ago

At 8:00 am, here's what we know about two airplanes: Airplane #1 has an elevation of 80870 ft and is decreasing at the rate of 4

wel

Let's begin by listing out the information given to us:

8 am

airplane #1: x = 80870 ft, v = -450 ft/ min

airplane #2: x = 5000 ft, v = 900ft/min

We must note that the airplanes are moving at a constant speed. The equation for the airplanes is given by:

$\begin{gathered} E=x_1+vt----1 \\ E=x_2+vt----2 \\ where\colon E=elevation,ft;x=InitialElevation,ft; \\ v=velocity,ft\text{/}min;t=time,min \\ x_1=80,870ft,v=-450ft\text{/}min \\ E=80870-450t----1 \\ x_2=5,000ft,v=900ft\text{/}min \\ E=5000+900t----2 \end{gathered}$

We equate equations 1 & 2 to get the time both airlanes will be at the same elevation. We have:

$\begin{gathered} 5000+900t=80870-450t \\ \text{Add 450t to both sides, we have:} \\ 900t+450t+5000=80870-450t+450t \\ 1350t+5000=80870 \\ \text{Subtract 5000 from both sides, we have:} \\ 1350t+5000-5000=80870-5000 \\ 1350t=75870 \\ \text{Divide both sides by 1350, we have:} \\ \frac{1350t}{1350}=\frac{75870}{1350} \\ t=56.2min \\ \\ \text{After }56.2\text{ minutes, both airplanes will be at the same elevation} \end{gathered}$

The elevation at that time (when the elevations of the two airplanes are the same) is given by substituting the value of time into equations 1 & 2. We have:

$\begin{gathered} E_1=80870-450t \\ E_1=80870-450(56.2) \\ E_1=80870-25290 \\ E_1=55580ft \\ \\ E_2=5000+900t \\ E_2=5000+900(56.2) \\ E_2=5000+50580 \\ E_2=55580ft \\ \\ \therefore E_1\equiv E_2=55580ft \end{gathered}$

6 0

1 year ago

Simplify 4a+3b-(-2a-3b)

Talja [164]

4a+3b-(-2a-3b)
=4a+3b+2a+3b
=6a+6b
=6(a+b)

8 0

3 years ago

Please help with these too (10-15)

kakasveta [241]

10. 64in > 5ft
11. 2 mi < 3,333yds
12. 36yd 2 ft< 114 ft 2 in
13. They are =
14. 4ft 7in < 56 in
15. 25 ft > 8yd 11 in

4 0

3 years ago