The ratio of their perimeters is still 7:20. The poster is a rectangle shape. If the length of each side of a poster is proportional to the other by a certain ratio, the sum of the lengths of all sides is also proportional by the same ratio. You can suppose the lengths of four sides of poster A are 7a, 7b, 7c, 7d, so poster B has 20a, 20b, 20c, 20d. (7a+7b+7c+7d)/(20a+20b+20c+20d)=7(a+b+c+d)/20(a+b+c+d)=7/20.

4 0

3 years ago

The following data show the prices of different types of outfits at a store: $2, $2, $28, $26, $25, $27, $25, $27, $26, $28, $30

wlad13 [49]

Answer:

The box plot will have its left tail longer than the right tail becuase a few exceptionally low prices make the distribution skewed to the left.

Step-by-step explanation:

As seen in the attached file, the box plot has its left tail longer than the right tail because of the exceptionally low prices that is :$2

Firstly arranging the data in increasing order:

$2,$2,$25,$25,$26,$26,$27,$27,$28,$28,$30

Median of the data = 26 (since there are odd numbers)

Lower quartile (Q1) = 25

Upper quartile (Q2) = 26

By plotting the box plot we conclude that the left tail is longer than the right tail.

4 0

4 years ago

ANSWER ASAPPPPPPPPPP////

Mamont248 [21]

3x^2 - 2x^2y + 2xy^2 + 4y^2 + xy^2 - y^2 + 2x^2y
= 3x^2 + 3y^2 + 3xy^2

answer
3x^2
3y^2
3xy^2

6 0

4 years ago

What is the solution to the linear equation? 2.8y + 6 + 0.2y = 5y – 14 y = –10 y = –1 y = 1 y = 10

svp [43]

2.8y + 6 + 0.2y = 5y – 14

Simplify the left side:

3y +6 = 5y-14

Subtract 3y from both sides:

6 = 2y -14

Add 14 to each side:

2y =20

Divide both sides by 2:

y = 20 / 2

y = 10

5 0

3 years ago

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