Answer:
y+7= -6/5(x+3)
Step-by-step explanation:
Point slope form for a line is given by
y-y1 = m(x-x1) where m is the slope and (x1, y1) is a point on the line
y - -7 = -6/5(x - -3)
y+7= -6/5(x+3)
Answer:
t=0.64
Step-by-step explanation:
h = -16t^2 +4t +4
We want h =0 since it is hitting the ground
0 = -16t^2 +4t +4
Using the quadratic formula
a = -16 b = 4 c=4
-b ± sqrt( b^2 -4ac)
----------------------------
2a
-4 ± sqrt( 4^2 -4(-16)4)
----------------------------
2(-16)
-4 ± sqrt( 16+ 256)
----------------------------
-32
-4 ± sqrt( 272)
----------------------------
-32
-4 ± sqrt( 16*17)
----------------------------
-32
-4 ± sqrt( 16) sqrt(17)
----------------------------
-32
-4 ± 4 sqrt(17)
----------------------------
-32
Divide by -4
1 ± sqrt(17)
----------------------------
8
To the nearest hundredth
t=-0.39
t=0.64
Since time cannot be negative
t=0.64
We start by finding the intercept of the line: what does y equal when x=0? and what does x equal when y=0?
• intercept in x
y = 12 + 2x
0 = 12 + 2x
-12 = 2x
-6 = x
• intercept in y
y = 12 + 2x
y = 12 + 2(0)
y = 12 + 0
y = 12
Now we find three more points giving y a value and finding x
y = 12 + 2x
2 = 12 + 2x
2-12 = 2x
-10 = 2x
-5 = x
y = 12 + 2x
6 = 12 + 2x
6 - 12 = 2x
-6 = 2x
-3 = x
y = 12 + 2x
14 = 12 + 2x
14 - 12 = 2x
2 = 2x
1 = x
Notice how I gave y even numbers as values since we would have to divide with 2 at the end.
Sol. {(-6,0)(0,12)(-5,2)(-3,6)(1,14)}
Yes, we need the sisters age to find it the answer, not trying to be rude we just need the sisters age.
