Question

Solve the following quadratic equation using the quadratic formula. Which of the following expressions gives the numerators of the solutions?
10x^2- 19x + 6 = 0

Answer 1

The quardratic equation is ax^2+bx+c=0

10x^2-19x+6=0

where a=10,b= - 19 c=6

quadratic formula=$-b(+-) \sqrt{b^2-4ac}/2a$

u solve it now