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3 years ago

15

Solve the following quadratic equation using the quadratic formula. Which of the following expressions gives the numerators of t

he solutions?
10x^2- 19x + 6 = 0

1 answer:

Doss [256]3 years ago

5 0

The quardratic equation is ax^2+bx+c=0

10x^2-19x+6=0

where a=10,b= - 19 c=6

quadratic formula= $-b(+-) \sqrt{b^2-4ac}/2a$

u solve it now

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3 years ago

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If the second term of a geometric sequence of real numbers is -2 and the fifth term is 16 then what is the fourteenth term?

Agata [3.3K]

<h3>Given</h3>

A geometric sequence such that ...

$a_2=-2\quad\text{and}\quad a_5=16$

<h3>Find</h3>

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