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viktelen [127]
2 years ago
10

Ribosomes can be found on the surface of the endoplasmic reticulum and suspended in the cytoplasm.

Biology
1 answer:
Alisiya [41]2 years ago
5 0

True.

Ribosomes are organelles inside a cell made up of protein and ribosomal RNA (rRNA).

Ribosomes synthesize proteins by linking amino acids together. Some ribosomes float freely in the cytosol of a cell, while others bind to the endoplasmic reticulum.

Free ribosomes are those found floating freely in the cell cytosol. They mainly manufacture proteins needed for the cell's own use.

Bound ribosomes are found "bound" to the endoplasmic reticulum creating what is known as rough endoplasmic reticulum. Most of the proteins made by these bound ribosomes are transported outside the cell for use in other parts of the body.


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What is a gene that has two positive transcription factors called
adoni [48]

Answer:

Transcription factors

Explanation:

They are part of the cell's core transcription toolkit, needed for the transcription of any gene. RNA polymerase binds to a promoter with help from a set of proteins called general transcription factors.

5 0
2 years ago
Conception is the moment a sperm meets an egg resulting in pregnancy. <br> a. True<br> b. False
oee [108]
A. True
Conception is basically the action of conceiving a child.
In conclusion, when a sperm meets an egg, the egg gets fertilized leading to pregnancy.
8 0
3 years ago
Read 2 more answers
Suppose "A" is a dominant gene for the ability to taste phenylthiocarbamide and "a" is a recessive gene for the inability to tas
dexar [7]

Complete question:

Suppose "A" is a dominant gene for the ability to taste phenylthiocarbamide and "a" is a recessive gene for the inability to taste it. Which couples could possibly have both a child who tastes it and a child who does not?​

a. father AA, mother aa

b. father Aa, mother AA

c. father Aa, mother Aa

d. father AA, mother AA

Answer:

c. father Aa, mother Aa

Explanation:

According to the given information, the ability to taste phenylthiocarbamide is a dominant trait and is imparted by the allele "A". This phenotype would be expressed in both homozygous and heterozygous conditions. The non-taster phenotype would be expressed in the homozygous recessive genotypes only.  

To have both taster and non-taster children, both the parents should have at least one copy of the recessive allele. Among the given options, the father with genotype Aa and the mother with genotype Aa have the possibility to have both taster and non-taster children.

Aa x Aa= 3/4 taster (1/4 AA and 1/2 Aa): 1/4 non-taster (1/4 aa)

4 0
3 years ago
1. Bacteria reproduce rapidly through binary fisson
Alchen [17]
I think the answer is offspring
5 0
2 years ago
You are doing an experiment and plated E. coliin different medias. Media A has onlyglucose, B has only lactose, and media C has
krek1111 [17]

Answer:

A. Glucose:

As lactose is absent will follow the glucose metabolism, so the lac repressor will hold tightly with the operator which leads to the prevention of transcription as RNA polymerase can not bind to promoter so no lactose metabolism.

B. lactose:

In the case or wild mutant lactose metabolism will occur as lactose is present, allolactose binds to the lac repressor thus the operator and promoter are free so transcription starts.  The same result will be in all test except in the case of a mutant repressor.

C. glucose and lactose:

In this case, diauxic growth will occur. This growth takes place when two sugars are present in the media. The preferred sugar will be consumed first That is glucose. Then a lag phase will come which will be followed by the second sugar metabolism that is lactose.  the given two cases :

Lactose will be metabolized first, as operator site mutation prevents repressor protein binding and thus will lead to the constitutive synthesis of lac operon in test B.   The same thing will happen, as in this case also, constitutive synthesis of lac operon will happen in test C.

Cultures grown in the presence of both glucose and lactose are metabolizing lactose. In the test (b) and (c) will be responsible due to constitutive synthesis of lac operon will happen.

6 0
3 years ago
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