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wolverine [178]

3 years ago

11

max has 623.22 in his checking account and a check that he wrote to his landlord for 625.00 was just deposited. This will result

in which of the following fees

2 answers:

Marta_Voda [28]3 years ago

8 0

Max will be missing $1.78 in his account. Is that one of the fee choices?

saul85 [17]3 years ago

6 0

Answer:

Step-by-step explanation:

Overdraft Fee

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Help pls this is really confusing

Ipatiy [6.2K]

Step-by-step explanation:

so the smaller one is two right? we can divide 96 by 2 to get 48 for each one

to find the bigger we simply multiply 48 by 5 to get 240

7 0

3 years ago

You can ride your bike around your block twice and the whole neighborhood once in 10 minutes. You can ride your bike around your

Bond [772]

I THINK,4=31
1=?
(1*31)/4=x
X=31/4
X=7.75minute to ride around the neighborhood once
It may not be correct

6 0

2 years ago

What are some uses for the distance formula?

lbvjy [14]

To find the area of a building.
and to make a small farm

8 0

2 years ago

Dianne drew a triangle with coordinates (1,3), (3,2) and (4,2) she drew an image of the triangle with coordinates (21,3) ,(23,2)

Bond [772]

Answer:

ttrhrtherhhhtrhtr

Step-by-step explanation:

6 0

3 years ago

Simplify the expression below and write it as a single logarithm:

OLEGan [10]

The simplification of 3log(x + 4) – 2log(x – 7) + 5log(x - 2) - log(x^2) is $\log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

<u>Solution:</u>

Given, expression is $3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

We have to write in as single logarithm by simplifying it.

Now, take the given expression.

$\rightarrow 3 \log (x+4)-2 \log (x-7)+5 \log (x-2)-\log \left(x^{2}\right)$

Rearranging the terms we get,

$\left.\rightarrow 3 \log (x+4)+5 \log (x-2)-2 \log (x-7)+\log \left(x^{2}\right)\right)$

$\text { since a } \times \log b=\log \left(b^{a}\right)$

$\rightarrow \log (x+4)^{3}+\log (x-2)^{5}-\left(\log (x-7)^{2}+\log \left(x^{2}\right)\right)$

$\text { We know that } \log a \times \log b=\log a b$

$\rightarrow \log \left((x+4)^{3} \times(x-2)^{5}\right)-\left(\log \left((x-7)^{2} \times\left(x^{2}\right)\right)\right.$

$\text { We know that } \log a-\log b=\log \frac{a}{b}$

$\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

Hence, the simplified form $\rightarrow \log \left(\frac{(x+4)^{3} \times(x-2)^{5}}{(x-7)^{2} \times x^{2}}\right)$

4 0

3 years ago

Read 2 more answers