Answer:
$20-$12=
Step-by-step explanation:
20-12=8
Answer:
The line is horizontal and the slope is 0.
Step-by-step explanation:
Any line that is horizontal has a slope of 0.
Answer:
B
Step-by-step explanation:
Simple interest is based on the principal amount of a loan or deposit.
Step-by-step explanation:
Take the first derivative


Set the derivative equal to 0.




or

For any number less than -1, the derivative function will have a Positve number thus a Positve slope for f(x).
For any number, between -1 and 1, the derivative slope will have a negative , thus a negative slope.
Since we are going to Positve to negative slope, we have a local max at x=-1
Plug in -1 for x into the original function

So the local max is 2 and occurs at x=-1,
For any number greater than 1, we have a Positve number for the derivative function we have a Positve slope.
Since we are going to decreasing to increasing, we have minimum at x=1,
Plug in 1 for x into original function


So the local min occurs at -2, at x=1
The linear relationship which exists between the change in weight and number of days of hibernation in a hedgedog can be modeled using the equation y = - 0.03 + 0
- Change in weight per day of hibernation = - 0.03
- Change in weight for 115 days = - 3.45 ounces
A linear model can be created using the data in the table given using a regression calculator or excel ;
The linear model obtained in the form y = m + bx is :
- y = - 0.03x + 0
- y = change in weight
- x = number of days of hibernation
- Intercept = 0
- Slope = -0.03
- The slope value of the function gives the change in weight value per number of days of hibernation ; which is -0.03.
- Using the regression equation, substitute, the vlaue of x = 115
- -0.03(115) + 0 = - 3.45
Therefore, the change in weight after 115 days of hibernation is - 3.45 ounces.
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