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kiruha [24]
2 years ago
13

Jane is painting her room. She mixes 3 pints of blue paint with 4 pints of red paint to get her desired color. Which equation ca

n be used to find the number of pints of blue paint (x) Jane should mix with 16 pints of red paint?
Mathematics
2 answers:
jeyben [28]2 years ago
7 0

Answer:

3/4 = 16/x

Step-by-step explanation:

Set up the original ratio: 3:4 (a.k.a. 3/4 or 3 to 4)

Because 16 correlates to red paint and 3 correlates to red paint the will be in the same location (as the numerator or denominator).

Also, the amount of blue paint is unknown so that is <u>x</u>. <u>4</u> also represents blue paint, so <u>4</u> and <u>x</u> will also be on the same level (as the numerator of denominator).

Setting up the equation: 3/<u>4</u> = 16/<u>x</u>

Lady bird [3.3K]2 years ago
5 0
Well if she added three blue and four red originally, and is now using 16 red then we would divide 16 by the original four. Which means to get the number of blue we are gonna end up multiplying by four. So three times four is twelve. Which means she would use 12 blue and 16 red to get the same color she got with 3 blue and 4 red earlier. The equation, lets use x for blue and y for red, would be 4(3x + 4y) = desired color
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inna [77]

Answer:

\displaystyle \sin(A+B)=\frac{3008}{3233}

Step-by-step explanation:

We are given that:

\displaystyle \cos(A)=\frac{60}{61}\text{ and } \tan(B)=\frac{45}{28}

And that the two angles <em>A</em> and <em>B</em> are both in QI (positive acute angles).

Given this, we want to determine the value of sin(A + B).

Recall that cosine is the ratio of the adjacent side to the hypotenuse. Using this information, we can determine the opposite side with respect to <em>A:</em>

<em />\displaystyle o=\sqrt{61^2-60^2}=\sqrt{121}=11<em />

<em />

Likewise, for <em>B</em>, tangent gives the ratio of the opposite side to the adjacent. Using this information, we can determine the hypotenuse of <em>B:</em>

<em />h=\sqrt{45^2+28^2}=\sqrt{2809}=53<em />

<em />

In conclusion:

With respect to <em>A</em>, the adjacent side is 60, the opposite side is 11, and the hypotenuse is 61.

With respect to <em>B, </em>the adjacent side is 28, the opposite side is 45, and the hypotenuse is 53.

We can rewrite our original expression as:

\sin(A+B)=\sin(A)\cos(B)+\sin(B)\cos(A)

And since <em>A</em> and <em>B</em> are both in QI, all trigonometric ratios will be positive.

Using the above conclusions, substitute:

\displaystyle \sin(A+B)=\left(\frac{11}{61}\right)\left(\frac{28}{53}\right)+\left(\frac{45}{53}\right)\left(\frac{60}{61}\right)

Simplify. Hence:

\displaystyle \sin(A+B)=\frac{308+2700}{3233} = \frac{3008}{3233}

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Step-by-step explanation:

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