How do you solve (Arc)QPT if <QZT = 120
1 answer:
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Answer:
7 n
Step-by-step explanation:
28 4n
divide by 4 on both sides
7 n
Answer:
1-
P(X=1) = 1/36
P(X=2) = 3/36 = 1/12
P(X=3) = 5/36
P(X=4) = 7/36
P(X=5) = 9/36 = ¼
P(X=6) = 11/36
2-
7/36
Step-by-step explanation:
1-
Attached, you will find a table with the possible values of X.
(See table attached)
As we can see, there are 36 entries so,
<em>P(X=1) = 1/36 </em>
<em> </em>
<em>P(X=2) = 3/36 = 1/12 </em>
<em> </em>
<em>P(X=3) = 5/36 </em>
<em> </em>
<em>P(X=4) = 7/36 </em>
<em> </em>
<em>P(X=5) = 9/36 = ¼ </em>
<em> </em>
<em>P(X=6) = 11/36 </em>
2-
It can be noticed that the only possible value of X which is divisible by 4 is 4 and there are 7 entries in the table, so
P(X divisible by 4) = P(X=4) = 7/36
