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3 years ago

How do you solve (Arc)QPT if <QZT = 120

Mathematics

1 answer:

yuradex [85]3 years ago

7 0

By definition, the arc length is given by:
arc = R * theta * ((2 * pi) / 360)
Where,
theta: angle in degrees
R: radio
We have then:
(Arc) QPT if <QZT = 120:
theta = 360-120 = 240 degrees
R = 13.5 units
Substituting values we have:
(Arc) QPT = R * theta * ((2 * pi) / 360)
(Arc) QPT = (13.5) * (240) * ((2 * pi) / 360)
(Arc) QPT = 56.55 units
Answer:
(Arc) QPT = 56.55 units

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