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Ahat [919]
3 years ago
11

How do you solve (Arc)QPT if <QZT = 120

Mathematics
1 answer:
yuradex [85]3 years ago
7 0
By definition, the arc length is given by:
 arc = R * theta * ((2 * pi) / 360)
 Where,
 theta: angle in degrees
 R: radio
 We have then:
 (Arc) QPT if <QZT = 120:
 theta = 360-120 = 240 degrees
 R = 13.5 units
 Substituting values we have:
 (Arc) QPT = R * theta * ((2 * pi) / 360)
 (Arc) QPT = (13.5) * (240) * ((2 * pi) / 360)
 (Arc) QPT = 56.55 units
 Answer:
 
(Arc) QPT = 56.55 units
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(5.217) standard deviation = 8.88

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(5.130) P(X> or = U) = 0.7058

Step-by-step explanation:

The table of the statistic is set up as shown in attachment.

(5.216) mean = summation of all X ÷ no of data.

mean = 432/7 = 61.71 birds

(5.217)Standard deviation = √ sum of the absolute value of difference of X from mean ÷ number of data

S = √ /X - mean/ ÷ 7

= √551.428/7

S = 8.88

(5.218) P (X> or = 60)

= P(Z> or =60 - 61.71/8.8 )

= P(Z>or= - 0.192)

= 1 - P(Z< or = 0.192)

= 1- 0.0762

= 0.9238

(5.219)the 15th percentile=15/100 × 7

15th percentile = 1.05

The value is the number in the first position and that is 79,

L= 79

85th percentile = 85/100 × 7 = 5.95

The value is the number in the 6th position, and that is 69

U = 69

5.130) P(X>or = 60)

= P(Z>or= 69 - 61.71/8.8)

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= 1 - P(Z< or = 0.8209)

= 1 - 0.2942

= 0.7058

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3 years ago
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