All categories

3 years ago

How do you solve (Arc)QPT if <QZT = 120

Mathematics

1 answer:

yuradex [85]3 years ago

7 0

By definition, the arc length is given by:
arc = R * theta * ((2 * pi) / 360)
Where,
theta: angle in degrees
R: radio
We have then:
(Arc) QPT if <QZT = 120:
theta = 360-120 = 240 degrees
R = 13.5 units
Substituting values we have:
(Arc) QPT = R * theta * ((2 * pi) / 360)
(Arc) QPT = (13.5) * (240) * ((2 * pi) / 360)
(Arc) QPT = 56.55 units
Answer:
(Arc) QPT = 56.55 units

You might be interested in

15b^2+20y^3<br> Find the greatest common factor

Andrew [12]

Answer:

Hope this helps!

Step-by-step explanation:

The GCF is 5

8 0

3 years ago

You have found the ages (in years) of 5 gorillas. Those gorillas were randomly selected from the 29 gorillas at your local zoo:

zalisa [80]

Answer:

the answer is 10

Step-by-step explanation:

(8+4+14+16+8)/5

8 0

2 years ago

There is 25 coins in a bag, 5 of them are quarters. What is the probability of getting a quarter? Express as all four types of p

Zina [86]

Answer:

Step-by-step explanation:

The ptobability of getting a quarter is 5/25 to the simpliest form is 1/5

The four probability is basic probability, compound event, independent and dependent event and the probability line.

I hope it'll help you much

Thank you for asking

8 0

3 years ago

What is the area? (IXL)

Zina [86]

Answer:

45 square meters

Step-by-step explanation:

we know that

The area of trapezoid is equal to

$A=\frac{1}{2}(b1+b2)h$

where

b1 and b2 are the parallel bases

h is the height of trapezoid (perpendicular distance between the parallel bases)

we have

$b1=6\ m\\b2=9\ m\\h=6\ m$

substitute

$A=\frac{1}{2}(6+9)6$

$A=45\ m^2$

3 0

4 years ago

the hardcover version of a book weighs 7 ounces while its paperback version weighs 5 ounces. Forty-five copies of the book weigh

Nuetrik [128]

Keywords:

<em>System of equations, variables, hardcover version, paperback version, books </em>

For this case we must construct a system of two equations with two variables. Let "h" be the number of hardcover version books, and let "p" be the number of paperback version books. If the hardcover version of a book weighs 7 ounces and the paperback version weighs 5 ounces, to reach a total of 249 ounces we have:

$7h + 5p = 249$ (1)

On the other hand, if there are Forty-five copies of the book then:

$h + p = 45$ (2)

If from (2) we clear the number of books paperback version we have:

$p = 45-h$

As each paperback version book weighs 5 ounces, to obtain the total weight of the paperback version books, represented by "x" in the table shown, we multiply $5 * p = 5 (45-h)$

So, $x = 5 (45-h)$

Answer:

$x = 5 (45-h)$

Option D

8 0

3 years ago

Read 2 more answers