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3 years ago

Https://screenshots.firefox.com/cxfIjV7PcUHa4HAl/lms.thinkthroughmath.com

1 answer:

8 0

Volume of rectangular prism is first edge*second edge*third edge (product of
prism dimensions)
1st edge has 4 small cubes , edge of the small cube=1/4,
so 1st edge of the large cube =1/4*4=4/4 (it could be written as 1)
2d edge has 3 small cubes , so 2d edge= 3*1/4=3/4
3d edge has also 3 small cubes , so 3d edge= 3*1/4=3/4
Volume= first edge*second edge*third edge=4/4*3/4*3/4=1*3/4*3/4=9/16
Answer 4/4*3/4*3/4=9/16

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Really need help with this paper

Darina [25.2K]

Answer:

The answer to your question is below

Step-by-step explanation:

1.- (2b - 1) (b + 8) = 0

2b - 1 = 0 b + 8 = 0

b = 1/2 b = -8

2.- (x + 3)(x - 12) = 0

x + 3 = 0 x - 12 = 0

x = -3 x = 12

3.- (4b+ 7)(b + 11)

4b + 7 = 0 b + 11 = 0

b = -7/4 b = -11

4.- (k - 8)(k + 6)

k - 8 = 0 k + 6 = 0

k = 8 k = -6

5.- (2n + 12)(5n+ 10)

2n + 12 = 0 5n + 10 = 0

n = -12/2 = -6 n = -10/5 = -2

6.- (w - 3)(3w - 7)

w - 3 = 0 3w - 7 = 0

w = 3 w = 7/3

7.- (6n - 5)(n - 10)

6n - 5 = 0 n - 10 = 0

n = 5/6 n = 10

8.- (n + 12)((4n + 7)

n + 12 = 0 4n + 7 = 0

n = -12 n = -7/4

9.- (3b + 4)(5b - 10)

3b + 4 = 0 5b - 10 = 0

b = -4/3 b = 10/5 = 2

10.- (p - 6)(p + 10)

p - 6 = 0 p + 10 = 0

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3 0

3 years ago

Determine which equation is parallel to the line JK and which is perpendicular to like JK

sattari [20]

Answer:

If the equation of JK is y = mx + c, then y = mx + c' is the equation of the straight line parallel to above and $y = - \frac{1}{m}x + b$ will be perpendicular to that.

Step-by-step explanation:

Let us assume that the line JK has the equation in slope-intercept form as

y = mx + c ............. (1)

Therefore, the equation has slope = m

Now, any straight line having an equation with slope m will be parallel to line JK.

So, the equation of the straight line which is parallel to equation (1) will be

y = mx + c', where, c' is any real constant.

Now, let us assume that another straight line having equation

y = nx + a is perpendicular to the line JK i.e. equation (1).

Now, we know if two lines are perpendicular to each other then the product of their slopes will be - 1.

So, mn = - 1

⇒ $n = - \frac{1}{m}$

Therefore, the equation of a straight line which is perpendicular to equation (1) will be $y = - \frac{1}{m}x + b$ where b is any real constant. (Answer)

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4 years ago

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igor_vitrenko [27]

Answer:

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6 0

3 years ago

Write 2 4/7 as an improper fraction

laila [671]

Multiply 2 by 7, which is 14, and add it to the 4 in the numerator. The fraction becomes 18/7

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4 years ago

5.) What is the GCF of the following<br> 6x2 and 12x3

algol13

Answer: 12
6x2 is 12 and 12x3 is 38.
We will first find the prime factorization of 12 and 36. After we will calculate the factors of 12 and 36 and find the biggest common factor number .

3 0

3 years ago