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3 years ago

Help PLEASE LIKE ACC STEP BY STEP FIND X PLZ

Mathematics

1 answer:

nikklg [1K]3 years ago

8 0

Answer:

Step-by-step explanation:

The sum of interior angles in a rectangle is 360°

98 + 98 + 98 + 2x = 360

294 + 2x = 360

2x = 66°

x = 33

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If f(x) = 7x^2 - 3x +1 and g(x) = 3x - 2, find the following by matching.

Cloud [144]

f(x) = 7x² - 3x + 1

g(x) = 3x - 2

1. g(0) This means that x is 0, so you can plug in 0 for x in the equation:

g(x) = 3x - 2

g(0) = 3(0) - 2

g(0) = -2

2. g(1) x is 1

g(x) = 3x - 2

g(1) = 3(1) - 2

g(1) = 3 - 2

g(1) = 1

3. f(1) x is 1

f(x) = 7x²- 3x + 1

f(1) = 7(1)² - 3(1) + 1

f(1) = 7 - 3 + 1

f(1) = 5

4. f(x) = 7x²- 3x + 1

f(-2) = 7(-2)²- 3(-2) + 1

f(-2) = 7(4) + 6 + 1

f(-2) = 28 + 7

f(-2) = 35

4 0

3 years ago

John is living in New York, where the state sales tax is 8%. The total cost of his purchase was $50.00. What was the original pr

bogdanovich [222]

Let p be the pre-tax cost. Then 1.08p = $50. Solving for p, the pre-tax cost, we get:

p = ($50) / (1.08) = $46.30.

6 0

3 years ago

Which of the following is closest 27.8×9.6

Luda [366]

266.8 that’s the answer hope it helps

8 0

3 years ago

Read 2 more answers

What is the square root of -2i?

Studentka2010 [4]

Answer:

1-i and -1+i

Step-by-step explanation:

We are to find the square roots of $z=0-2i$ . First, convert from Cartesian to polar form:

$r=\sqrt{a^2+b^2}\\r=\sqrt{0^2+(-2)^2}\\r=\sqrt{0+4}\\r=\sqrt{4}\\r=2$

$\theta=tan^{-1}(\frac{b}{a})\\ \theta=tan^{-1}(\frac{-2}{0})\\\theta=\frac{3\pi}{2}$

$z=2(\cos\frac{3\pi}{2}+i\sin\frac{3\pi}{2})$

Next, use the formula $\displaystyle \sqrt[n]{r}\biggr[\cis\biggr(\frac{\theta+2\pi k}{n}\biggr)\biggr]$ where $\displaystyle k=0,1,2,...\:,n-1$ to find the square roots:

When k=1

$\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(1)}{2}\biggr)\biggr]$

$\displaystyle \sqrt{2}\biggr[cis\biggr(\frac{3\pi}{4}+\pi\biggr)\biggr]$

$\sqrt{2}\biggr(cis\frac{7\pi}{4}\biggr)$

$\sqrt{2}(\cos\frac{7\pi}{4}+i\sin\frac{7\pi}{4})\\ \\\sqrt{2}(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i)\\ \\1-i$

When k=0

$\displaystyle \sqrt[2]{2}\biggr[cis\biggr(\frac{\frac{3\pi}{2}+2\pi(0)}{2}\biggr)\biggr]$

$\sqrt{2}\biggr(cis\frac{3\pi}{4}\biggr)$

$\sqrt{2}(\cos\frac{3\pi}{4}+i\sin\frac{3\pi}{4})\\ \\\sqrt{2}(-\frac{\sqrt{2}}{2}+\frac{\sqrt{2}}{2}i)\\ \\-1+i$

Thus, the square roots of -2i are 1-i and -1+i

4 0

2 years ago

7. The new York Volleyball Association

Yuri [45]

Using a geometric sequence, it is found that after 3 rounds, 8 teams are left.

In a geometric series, the quotient between consecutive terms is always the same, and it is called common ratio q.

The general equation of a geometric series is given by:

$a_n = a_1q^{n-1}$

In which $a_1$ is the first term.

In this problem:

64 teams were invited, thus $a_1 = 64$ .
After each round, half the teams are eliminated, thus $q = \frac{1}{2}$ .

The number of teams after 3 rounds is the 4th term of sequence, as the first is the initial number(0 rounds), thus:

$a_n = a_1q^{n-1}$

$a_4 = 64\left(\frac{1}{2}\right)^{4-1}$

$a_4 = 8$

After 3 rounds, 8 teams are left.

A similar problem is given at brainly.com/question/25317689

4 0

3 years ago