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3 years ago

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HELP PLEASE!! An artist is drawing three large circles on the ground with diameters of 6m, 10m, and 13m. Identify the area of ea

ch circle rounded to the nearest tenth of a meter.

1 answer:

Romashka-Z-Leto [24]3 years ago

4 0

Answer:

$A1=28.3\ m^{2}$ , $A2=78.5\ m^{2}$ , $A3=132.7\ m^{2}$

Step-by-step explanation:

we know that

The area of a circle is equal to

$A=\pi r^{2}$

Part 1) Find the area of the circle with diameter 6 m

we have

$r=6/2=3\ m$ -----> the radius is half the diameter

substitute the values

$A1=(3.14)(3)^{2}=28.3\ m^{2}$

Part 2) Find the area of the circle with diameter 10 m

we have

$r=10/2=5\ m$ -----> the radius is half the diameter

substitute the values

$A2=(3.14)(5)^{2}=78.5\ m^{2}$

Part 3) Find the area of the circle with diameter 13 m

we have

$r=13/2=6.5\ m$ -----> the radius is half the diameter

substitute the values

$A3=(3.14)(6.5)^{2}=132.7\ m^{2}$

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Expanded form of (-p) ³

8_murik_8 [283]

Answer:

(- p) × (- p) × (- p)

Step-by-step explanation:

(-p)³

(- p) × (- p) × (- p)

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3 years ago

A forest covers 69,000 acres. A survey finds that 0.6% of the forest is old-growth trees. How many acres of old-growth trees

JulijaS [17]

Answer:

414 acres.

Step-by-step explanation:

To answer this question we have to multiply the percent by the total acres.

Remember that when multiplying percents we have to move the decimal 2 places to the left.

So, the equation looks like this:

$69,000 * .006 = 414$

Therefore, there are 414 acres that are old-growth trees.

We can check our answer by dividing 414 by 69,000.

414/69000 = .006

.006 * 100 = .6

<em>I hope this helps!!</em>

<em>- Kay :)</em>

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3 years ago

What is the fifth term in the binomial expansion of (x + 5)^8?O 175,000x³O 43,750x4O 3,125x5O 7,000x

enyata [817]

Solution:

Given the expression below

$(x+5)^8$

Applying the binomial theorem formula

$\begin{gathered} \left(a+b\right)^n=\sum_{k=0}^n{\binom{n}{k}}a^{n-k}b^k \\ Where \\ a=x \\ b=5 \\ n=8 \\ k=4\text{ i.e. fifth term} \end{gathered}$

For the fifth term, i.e

$\sum_{k=4}^8{\binom{8}{4}}x^{8-4}5^4=\frac{8!}{4!(8-4)!}\cdot x^4\cdot(625)=(70)(625)(x^4)=43750x^4$

Hence, the fifth terms is

$43750x^4$

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1 year ago

Solve for the sum of the measures of the interior angles of a 14-gon. A. 12° B. 14° C. 2160° D. 2520°

Goshia [24]

The sum of the interior angles of a polygon is given by
180(n-2)
Where n is the number of sides of the polygon.
Sum = 180(14 - 2)
= 2160°
The answer is C

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3 years ago

How long will it take the ball to reach the ground

SSSSS [86.1K]

When the ball reaches the ground, its height is 0.
We set the height function equal to zero and solve for t, the time.

h = -16t^2 + 250

-16t^2 + 250 = 0

16t^2 - 250 = 0

$(4t + \sqrt{250})(4t - \sqrt{250}) = 0$

$4t + \sqrt{250} = 0$ or $4t - \sqrt{250} = 0$

$4t = -\sqrt{250}$ or $4t = \sqrt{250}$

$t = -\dfrac{\sqrt{250}}{4}$ or $t = \dfrac{\sqrt{250}}{4}$

We discard the negative solution since time must be positive.
The positive solution is

$t = \dfrac{\sqrt{250}}{4} \approx 4.0$

Answer: 4.0 seconds

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3 years ago