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GREYUIT [131]
3 years ago
15

HELP PLEASE!! An artist is drawing three large circles on the ground with diameters of 6m, 10m, and 13m. Identify the area of ea

ch circle rounded to the nearest tenth of a meter.

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0

Answer:

A1=28.3\ m^{2},A2=78.5\ m^{2},A3=132.7\ m^{2}

Step-by-step explanation:

we know that

The area of a circle is equal to

A=\pi r^{2}

Part 1) Find the area of the circle with diameter 6 m

we have

r=6/2=3\ m -----> the radius is half the diameter

substitute the values

A1=(3.14)(3)^{2}=28.3\ m^{2}

Part 2) Find the area of the circle with diameter 10 m

we have

r=10/2=5\ m -----> the radius is half the diameter

substitute the values

A2=(3.14)(5)^{2}=78.5\ m^{2}

Part 3) Find the area of the circle with diameter 13 m

we have

r=13/2=6.5\ m -----> the radius is half the diameter

substitute the values

A3=(3.14)(6.5)^{2}=132.7\ m^{2}

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2 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
Which expression is equivalent to 3 ( x + 10)
devlian [24]

Answer:

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Step-by-step explanation:

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Hope this helps.

8 0
3 years ago
What is the value of the numerical expression 5/8 - 5/12 (3 -1/4) + 2/3 ?
nasty-shy [4]
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= \dfrac{5}{8} -  \dfrac{5}{12} (2\dfrac{3}{4} )+  \dfrac{2}{3}

= \dfrac{5}{8} -  \dfrac{5}{12} (\dfrac{11}{4} )+  \dfrac{2}{3}

= \dfrac{5}{8} -  \dfrac{55}{48}+  \dfrac{2}{3}

= \dfrac{30}{48} -  \dfrac{55}{48}+  \dfrac{32}{48}

= \dfrac{7}{48}

6 0
3 years ago
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