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2 years ago

Please help will mark brainliest answer!

2 answers:

3 0

Based on the answer options there are it would be brown. I solved this by adding the numbers all together then dividing it by 4 and that gave me my answer.

Harrizon [31]2 years ago

3 0

Brown 6. i did the same thing as @ elizabethgreen said

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Is 1.7 greater than 1 7/9

Simora [160]

17 = 1 7/10

1.7 < 1 7/9

1.7 is less than 1 7/9

3 0

3 years ago

Read 2 more answers

7/8x=42<br><br> What is the value of x?

Artist 52 [7]

$\frac{7}{8}*x=42 \\ \\x=42: \frac{7}{8} \\ \\ x=42* \frac{8}{7} \\ \\ x= \frac{336}{7} \\ \\ \boxed{x=48}$

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2 years ago

What is the solution to the equation 9(w – 4) – 7w = 5(3w – 2)?

Yuliya22 [10]

Answer:

W= -2

Step-by-step explanation:

Simply the expression: 9(w – 4) – 7w = 5(3w – 2)

First step: 9w -36-7w = 15w-10

Second step: 2w-36=15w-10

Third step:-36+10=15w-2w

Fourth step:-26=13w

Fifth step: w= $\frac{-26}{13}$

Six step: w=-2

3 0

2 years ago

Read 2 more answers

One model for the spread of a virusis that the rate of spread is proportional to the product of the fraction of the population P

Darya [45]

Answer:

The differential equation for the model is

$\frac{dP}{dt}=kP(1-P)$

The model for P is

$P(t)=\frac{1}{1-0.99e^{t/447}}$

At half day of the 4th day (t=4.488), the population infected reaches 90,000.

Step-by-step explanation:

We can write the rate of spread of the virus as:

$\frac{dP}{dt}=kP(1-P)$

We know that P(0)=100 and P(3)=100+200=300.

We have to calculate t so that P(t)=0.9*100,000=90,000.

Solving the diferential equation

$\frac{dP}{dt}=kP(1-P)\\\\ \int \frac{dP}{P-P^2} =k\int dt\\\\-ln(1-\frac{1}{P})+C_1=kt\\\\1-\frac{1}{P}=Ce^{-kt}\\\\\frac{1}{P}=1-Ce^{-kt}\\\\P=\frac{1}{1-Ce^{-kt}}$

$P(0)= \frac{1}{1-Ce^{-kt}}=\frac{1}{1-C}=100\\\\1-C=0.01\\\\C=0.99\\\\\\P(3)= \frac{1}{1-0.99e^{-3k}}=300\\\\1-0.99e^{-3k}=\frac{1}{300}=0.99e^{-3k}=1-1/300=0.997\\\\e^{-3k}=0.997/0.99=1.007\\\\-3k=ln(1.007)=0.007\\\\k=-0.007/3=-0.00224=-1/447$

Then the model for the population infected at time t is:

$P(t)=\frac{1}{1-0.99e^{t/447}}$

Now, we can calculate t for P(t)=90,000

$P(t)=\frac{1}{1-0.99e^{t/447}}=90,000\\\\1-0.99e^{t/447}=1/90,000 \\\\0.99e^{t/447}=1-1/90,000=0.999988889\\\\e^{t/447}=1.010089787\\\\ t/447=ln(1.010089787)\\\\t=447ln(1.010089787)=447*0.010039225=4.487533$

At half day of the 4th day (t=4.488), the population infected reaches 90,000.

8 0

3 years ago

Translate the following expressions into equations

vichka [17]

Step-by-step explanation:

all work is pictured and shown

4 0

2 years ago