QUESTION 1
The given logarithmic expression is
We rewrite 
in the index form to base 4.
This implies that;
We now apply the power rule: 
.
Recall that logarithm of the base is 1.
QUESTION 2
The given logarithm is;
![\log_2(\sqrt[5]{32})](https://tex.z-dn.net/?f=%5Clog_2%28%5Csqrt%5B5%5D%7B32%7D%29)
![\log_2(\sqrt[5]{2^5})](https://tex.z-dn.net/?f=%5Clog_2%28%5Csqrt%5B5%5D%7B2%5E5%7D%29)
This is the same as;
The answer would be 1 by 3 y to the first power
Answer:
option 2 must be the correct answer because the two figure are congruent figure.
Answer:
d = 0.33
Step-by-step explanation:
First off, you want to get like terms next to each other. We'll move the numbers with variables on one side and normal numbers on the other. Since we're changing the sides of the equal sign they're on, this also changes whether their positive or negative.
d - d - 2d + 3d = 10 -7 + 8 - 10
Now that they're together, we can add or subtract them. The variables without numbers can be ones for this equation.
3d = 1
Now we divide 1 by 3 to find what d equals.
3d/3 = 1/3
d = 0.33
