In right triangle abc shown below, altitude cd is drawn to hypotenuse (ab). explain why δabc ∼ δacd.
1 answer:
<span>First prove that ∆CBD ~ ∆ABC.
Each triangle has a right triangle and each includes angle </span>B. <span> The triangles are similar.
You can use similar reasoning to show that </span><span>∆ACD ~ ∆ABC.
To show that ∆CBD ~ ∆ACD, begin by showing that angle</span>ACD = angle B because they are both complementary to angle<span>DCB. Then you can use Similarity Postulates.
</span>I found the image of the triangle that was missing the question! Attached triangle.
Each triangle has a right triangle and each includes angle </span>B. <span> The triangles are similar.
You can use similar reasoning to show that </span><span>∆ACD ~ ∆ABC.
To show that ∆CBD ~ ∆ACD, begin by showing that angle</span>ACD = angle B because they are both complementary to angle<span>DCB. Then you can use Similarity Postulates.
</span>I found the image of the triangle that was missing the question! Attached triangle.
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