Answer:
A
Step-by-step explanation:it would look like this 4(0.45+x)
you would distribute and solve for X
Answer:
Area of a square = side * 4
Step-by-step explanation:
Answer:

Step-by-step explanation:
From the image attached below;
We need to calculate the limits of x and y to find the double integral
We will notice that y varies from 1 to 2
The line equation for (0,1),(1,2) is:

y - 1 = x
The line equtaion for (1,2),(4,1) is:

-3(y-2) = (x -1)
-3y + 6 = x - 1
-x = 3y - 6 - 1
-x = 3y - 7
x = -3y + 7
This implies that x varies from y - 1 to -3y + 7
Now, the region D = {(x,y) | 1 ≤ y ≤ 2, y - 1 ≤ x ≤ -3y + 7}
The double integral can now be calculated as:

![\iint _D y^2 dA= \int ^2_1 \bigg[ 2xy ^2 \bigg]^{-3y+7}_{y-1} \ dy](https://tex.z-dn.net/?f=%5Ciint%20_D%20y%5E2%20dA%3D%20%5Cint%20%5E2_1%20%5Cbigg%5B%202xy%20%5E2%20%5Cbigg%5D%5E%7B-3y%2B7%7D_%7By-1%7D%20%20%5C%20dy)
![\iint _D y^2 dA= \int ^2_1 \bigg[2(-3y+7)y^2-2(y-1)y^2 \bigg ] \ dy](https://tex.z-dn.net/?f=%5Ciint%20_D%20y%5E2%20dA%3D%20%5Cint%20%5E2_1%20%5Cbigg%5B2%28-3y%2B7%29y%5E2-2%28y-1%29y%5E2%20%5Cbigg%20%5D%20%20%5C%20dy)
![\iint _D y^2 dA= \int ^2_1 \bigg[-6y^3 +14y^2 -2y^3 +2y^2 \bigg ] \ dy](https://tex.z-dn.net/?f=%5Ciint%20_D%20y%5E2%20dA%3D%20%5Cint%20%5E2_1%20%5Cbigg%5B-6y%5E3%20%2B14y%5E2%20-2y%5E3%20%2B2y%5E2%20%5Cbigg%20%5D%20%20%5C%20dy)
![\iint _D y^2 dA= \int ^2_1 \bigg[-8y^3 +16y^2 \bigg ] \ dy](https://tex.z-dn.net/?f=%5Ciint%20_D%20y%5E2%20dA%3D%20%5Cint%20%5E2_1%20%5Cbigg%5B-8y%5E3%20%2B16y%5E2%20%20%5Cbigg%20%5D%20%20%5C%20dy)
![\iint _D y^2 dA= \bigg[-8(\dfrac{y^4}{4}) +16(\dfrac{y^3}{3})\bigg ] ^2_1](https://tex.z-dn.net/?f=%5Ciint%20_D%20y%5E2%20dA%3D%20%20%5Cbigg%5B-8%28%5Cdfrac%7By%5E4%7D%7B4%7D%29%20%20%2B16%28%5Cdfrac%7By%5E3%7D%7B3%7D%29%5Cbigg%20%5D%20%5E2_1)
![\iint _D y^2 dA= \bigg[-8(\dfrac{16}{4}-\dfrac{1}{4}) +16(\dfrac{8}{3}-\dfrac{1}{3})\bigg ]](https://tex.z-dn.net/?f=%5Ciint%20_D%20y%5E2%20dA%3D%20%20%5Cbigg%5B-8%28%5Cdfrac%7B16%7D%7B4%7D-%5Cdfrac%7B1%7D%7B4%7D%29%20%20%2B16%28%5Cdfrac%7B8%7D%7B3%7D-%5Cdfrac%7B1%7D%7B3%7D%29%5Cbigg%20%5D)
![\iint _D y^2 dA= \bigg[-8(\dfrac{15}{4}) +16(\dfrac{7}{3})\bigg ]](https://tex.z-dn.net/?f=%5Ciint%20_D%20y%5E2%20dA%3D%20%20%5Cbigg%5B-8%28%5Cdfrac%7B15%7D%7B4%7D%29%20%20%2B16%28%5Cdfrac%7B7%7D%7B3%7D%29%5Cbigg%20%5D)



"Let There Be a Gas Phase"
There, a type of material called kimberlite magma causes the solid rock to break its way up from deeper into the mantle of Earth. The magma gathers fragments of rocks as it rises, like floodwaters gathering up silt and gravel. Diamonds are contained in some of these fragments.