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Brrunno [24]
3 years ago
6

Help me! Need answers to questions ii and iii please. Thanks x

Mathematics
1 answer:
Debora [2.8K]3 years ago
6 0
Ii.First ,expand: 5(x-2)=32
5x-10=32
bring 10 to the other side (add it to 32)
5x=42
divide both sides by 5 to get x
x=42/5
x=8.4

iii.Expand 5+2(x+3)=21
5+2x+6=21
bring 5 and 6 to the other side
2x=21-5-6
2x=10 divide both sides by 2
x=5
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Step-by-step explanation:

We have,

A ball is thrown into the air with an upward velocity of 36 ft/s. Its height h in feet after t seconds is given by the function :

h=-16t^2 + 36t + 10 ......(1)

Part (a) :

The maximum height reached by the ball is given by :

\dfrac{dh}{dt}=0\\\\\dfrac{d(-16t^2 + 36t + 10)}{dt}=0\\\\-32t+36=0\\\\t=\dfrac{36}{32}\\\\t=1.125\ s

Part (b) :

The maximum height of the ball is calculated by putting t = 1.125 in equation (1) such that :

h=-16(1.125)^2 + 36(1.125)+ 10\\\\h=30.25\ m

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